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3 years ago

Name all of the alkene isomers, c6h12, that contain an unbranched chain and that do not have e/z isomers.

Chemistry

1 answer:

Sonbull [250]3 years ago

3 0

Here we have to get the possible isomers of hexene C₆H₁₂ which have no branching and cis, trans form.

The alkene isomers those are possible for C₆H₁₂ without any branch and e/z isomers is 1-hexene.

The isomers are possible without any branch for C₆H₁₂ may be 1-hexene, 2-hexene and 3-hexene.

But without e/z isomers mean the structure should not have any cis, trans form.

Now the 2-hexene and 3-hexene both have cis, trans isomerism. Only 1-hexene will not have any branch chain and e/z isomers.

Thus the name of the alkene isomer having C₆H₁₂ formula is determined.

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Which of these is a biomass energy source the sun sugarcane natutal gas water

mixer [17]

I believe the answer is sugarcane

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2 years ago

COCl2(g) decomposes according to the equation above. When pure COCl2(g) is injected into a rigid, previously evacuated flask at

mestny [16]

<u>Answer:</u> The value of $K_p$ for the reaction at 690 K is 0.05

<u>Explanation:</u>

We are given:

Initial pressure of $COCl_2$ = 1.0 atm

Total pressure at equilibrium = 1.2 atm

The chemical equation for the decomposition of phosgene follows:

$COCl_2(g)\rightleftharpoons CO(g)+Cl_2(g)$

Initial: 1 - -

At eqllm: 1-x x x

We are given:

Total pressure at equilibrium = [(1 - x) + x+ x]

So, the equation becomes:

$[(1 - x) + x+ x]=1.2\\\\x=0.2atm$

The expression for $K_p$ for above equation follows:

$K_p=\frac{p_{CO}\times p_{Cl_2}}{p_{COCl_2}}$

$p_{CO}=0.2atm\\p_{Cl_2}=0.2atm\\p_{COCl_2}=(1-0.2)=0.8atm$

Putting values in above equation, we get:

$K_p=\frac{0.2\times 0.2}{0.8}\\\\K_p=0.05$

Hence, the value of $K_p$ for the reaction at 690 K is 0.05

3 0

2 years ago

What is the specific heat of a substance if 6527 J are required to raise the temperature of a 312 g sample by 15 degrees Celsius

Tanzania [10]

Answer:

1.395J/g°C

Explanation:

The following were obtained from the question:

Q = 6527J

M = 312g

ΔT = 15°C

C =?

Q = MCΔT

C = Q/MΔT

C = 6527/(312 x 15)

C = 1.395J/g°C

The specific heat capacity of the substance is 1.395J/g°C

3 0

3 years ago

15.0 mL of an unknown clear liquid is added to a 50 mL graduated cylinder. The mass of the liquid is determined to be 12.7 grams

sveticcg [70]

Answer:

$\boxed {\tt A. \ d=0.85 \ g/mL}$

Explanation:

Density is found by dividing the mass by the volume.

$d=\frac{m}{v}$

The mass of the liquid is 12.7 grams.

We know that 15 mL of this liquid was added to a 50 mL graduated cylinder. Therefore, the volume is 15 mL. The 50 mL is not relevant, it only tells us about the graduated cylinder.

$m= 12.7 \ g\\v= 15 \ mL$

Substitute the values into the formula.

$d=\frac{12.7 \ g}{ 15 mL}$

Divide.

$d=0.846666667 \ g/mL$

Round to the nearest hundredth. The 6 in the tenth place tells us to round the 4 to a 5.

$d \approx 0.85 \ g/mL$

The density of the liquid is about 0.85 grams per milliliter and choice A is correct.

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2 years ago

Write the formulas of the three singly chlorinated isomers formed when 2,2-dimethylbutane reacts with Cl2 in the presence of lig

Tems11 [23]

The molecule with same molecular formula but different arrangement of atoms is said to be an isomer.

When 2,2-dimethylbutane reacts with chlorine in the presence of light gives three isomers that is $CH_{3}C(CH_{3})_{2}CHClCH_{3}$ (3-chloro-2,2-dimethylbutane), $ClCH_{2}C(CH_{3})_{2}CH_{2}CH_{3}$ (1-chloro-2,2-dimethylbutane) and $ClCH_{2}CH_{2}C(CH_{3})_{2}CH_{3}$ (1-chloro-3,3-dimethylbutane).

In above case, the molecular formula of all isomers are same i.e. $C_{6}H_{13}Cl$ but chlorine is arranged in different positions of carbon. Thus, results isomers.

The reaction is shown in the image.

3 0

3 years ago