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Irina18 [472]
4 years ago
13

Name all of the alkene isomers, c6h12, that contain an unbranched chain and that do not have e/z isomers.

Chemistry
1 answer:
Sonbull [250]4 years ago
3 0

Here we have to get the possible isomers of hexene C₆H₁₂ which have no branching and cis, trans form.

The alkene isomers those are possible for C₆H₁₂ without any branch and e/z isomers is 1-hexene.

The isomers are possible without any branch for C₆H₁₂ may be 1-hexene, 2-hexene and 3-hexene.

But without e/z isomers mean the structure should not have any cis, trans form.

Now the 2-hexene and 3-hexene both have cis, trans isomerism. Only 1-hexene will not have any branch chain and e/z isomers.

Thus the name of the alkene isomer having C₆H₁₂ formula is determined.  

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Three isotopes of silicon have mass numbers of 28,29, and 30 with an average atomic mass of 28.086 what does this say about the
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Ar₂(Si) =29; the average atomic mass of isotope ²⁹Si.  

Ar₃(Si) =30; the average atomic mass of isotope ³⁰Si.  

Silicon (Si) is composed of three stable isotopes, ₂₈Si (92.23%), ₂₉Si (4.67%) and ₃₀Si (3.10%).

ω₁(Si) = 92.23%; mass percentage of isotope ²⁸Si.  

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ω₃(Si) = 3.10%; mass percentage of isotope ³⁰Si.

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To what volume should you dilute 134 mL of an 8.00 M CuCl2 solution so that 48.0 mL of the diluted solution contains 5.89 g CuCl
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Explanation:

Number of moles of CuCl2 initially present = volume * molar concentration

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