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Irina18 [472]
3 years ago
13

Name all of the alkene isomers, c6h12, that contain an unbranched chain and that do not have e/z isomers.

Chemistry
1 answer:
Sonbull [250]3 years ago
3 0

Here we have to get the possible isomers of hexene C₆H₁₂ which have no branching and cis, trans form.

The alkene isomers those are possible for C₆H₁₂ without any branch and e/z isomers is 1-hexene.

The isomers are possible without any branch for C₆H₁₂ may be 1-hexene, 2-hexene and 3-hexene.

But without e/z isomers mean the structure should not have any cis, trans form.

Now the 2-hexene and 3-hexene both have cis, trans isomerism. Only 1-hexene will not have any branch chain and e/z isomers.

Thus the name of the alkene isomer having C₆H₁₂ formula is determined.  

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kotykmax [81]

Explanation:

fractional distillation method is used to obtain petrol from petroleum...

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What is the net Ionic equation of HClO4(aq)+ NaOH(aq) = H2O(l)+ NaClO4(aq)
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H^+(aq) + OH^-(aq) ---> H2O(l) 

<span>Na^+ and ClO4^- are the spectator ions.</span>
7 0
3 years ago
The expected o-c-h angle in this molecule is degrees. the expected hybridization at the central carbon is
WINSTONCH [101]

Each neutral carbon atom contains four valence electrons and may form up to four electron domains. Possible hybridizations include

  • sp^{3}, four electron domains, as in ethane \text{C}_2\text{H}_6
  • sp^{2}, three electron domains, as in ethene \text{C}_2\text{H}_4
  • sp, two electron domains, as in ethyne \text{C}_2\text{H}_2

Molecules of each of the three hybridization demonstrate spatial configurations that would maximizes the separation between the electron domains.

  • Carbon atoms with a sp^{3} hybridization would demonstrate a tetrahedral configuration with a bond angle of approximately 109.5\textdegree{}
  • Carbon atoms with a sp^{2} hybridization would demonstrate a triangular planar configuration with a bond angle of 120\textdegree{}
  • Carbon atoms with a sp hybridization would demonstrate a linear configuration with a bond angle of 180\textdegree{}

Bond angles are characteristic of the spatial configuration of electron domains and identifies the hybridization of the central carbon atom.

Note that each hydrogen atom contains only one valence electron and would form only single bonds. It takes two valence electrons for oxygen atoms to achieve an octet such that each oxygen form only two bonds at a single time. Therefore given the fact that the carbon is bonded to both hydrogen and oxygen, only the following hybridizations are possible

  • sp^{3} in which the oxygen atom forms a carbon-oxygen double bond with the central carbon atom;
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3 0
3 years ago
When you have finished adding the necessary amount of NaOH to your beaker, what color will the litmus paper turn?
Svetllana [295]

<u>Answer:</u> The red litmus paper turns blue on dipping in NaOH solution.

<u>Explanation:</u>

Litmus paper is the indicator that detects the nature of the solution, whether it is acidic or basic.

There are 2 types of litmus paper:

  • <u>Red litmus paper:</u> This paper will turn blue if it is dipped in basic solution and will remain as such if it is dipped in acidic solution.
  • <u>Blue litmus paper:</u> This paper will turn red if it is dipped in acidic solution and will remain as such if it is dipped in basic solution.

NaOH is a strong base, so when a red litmus paper is dipped in the beaker having necessary amount of NaOH, the red litmus paper turns into blue.

7 0
3 years ago
After the solution reaches equilibrium, what concentration of zn2 (aq remains?
Fantom [35]
According to sources, the most probable answer to this query is that when solutions reaches equilibrium, the amount of concentration of two or more matter combined in this solution becomes equal. 

Thank you for your question. Please don't hesitate to ask in Brainly your queries. 
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