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Sav [38]
3 years ago
10

The force measured to move a sled was 10 N and the sled was moved 10 meters,

Physics
1 answer:
sergey [27]3 years ago
3 0

Answer:

work done would be I don't know

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What type of wave did you create when you pushed your arm back and forth?<br><br> plz help
IgorC [24]

Answer: It is a transverse wave ^^

Explanation:

8 0
3 years ago
A container has a large cylindrical lower part with a long thin cylindrical neck open at the top. The lower part of the containe
Brums [2.3K]

Answer:

8.6*10^5N

Explanation:

Pressure of the water = density of water * height of the water * acceleration due to gravity

Pressure of water = 1000*9.81*(2.5 + 8.50)

Pressure of the water = 107910 = 1.08*10^5

And Pressure = force / A

Force = Pressure * A(surface area of the container)

Force = 1.08*10^5 * 8 = 863280 = 8.6*10^5N

6 0
3 years ago
Some help me on this please
satela [25.4K]

Answer:

Changes in the object's momentum (answer D)

Explanation:

A net force will cause an object to change its velocity, and that will affect the object's momentum, which is defined by the product of the object's mass times its velocity.

So, select the last option (D) in the given list.

8 0
3 years ago
We can reasonably model a 90-W incandescent lightbulb as a sphere 5.7 cm in diameter. Typically, only about 5% of the energy goe
o-na [289]

Answer:

See answer

Explanation:

Given quantities:

\eta = 0.05\\ W=90[W]\\r=0.0285[m]

where \eta is the efficiency of the lightbulb (visible light is 5% of the total power), W is the total power of the lightbulb, r is the radius of the lightbulb in meters.

Intensity is power divided by area:

I =\frac{P}{A}

a) Now the effective power is \eta*W, therefore:

I =\frac{\eta*W}{\pi r^2}=\frac{0.05*90}{4\pi (0.0285)^2}=440.87[W/m^2]

b) Now the intensity is the average poynting vector is related to the magnitudes of the  maximum electric field and magnetic field amplitudes, following:

S_{average}= \frac{EB}{2\mu_{0}}[W/m]

now E and B are related:

E=cB\\ B=\frac{E}{c} and c=\frac{1}{\sqrt{\epsilon_{0} \mu_{0}}}

replace in S_{average}

S_{average}=I= \frac{c \epsilon_{0}E^2}{2}[W/m]

we replace the values and we get:

E= \sqrt{\frac{2I}{\epsilon_{0}c}}

E = \sqrt{\frac{2(440.8)}{8.85*10^{-12}3*10^8}}=576.24[V/m]

therefore

B=\frac{E}{c}=\frac{576.24}{3*10^{8}}=1.92*10^{-6}[T]

8 0
3 years ago
What does the kinetic theory state about the kinetic energy of gas molecules?
devlian [24]
<span>The kinetic energy of gas molecules is directly proportional to the Kelvin temperature of the gas</span>
7 0
4 years ago
Read 2 more answers
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