Answer:
![\tau =37.34\ N m](https://tex.z-dn.net/?f=%5Ctau%20%3D37.34%5C%20N%20m)
Explanation:
given,
mass of the weight = 8 Kg
distance = 0.55 m
angle below horizontal = 30°
torque about shoulder
![\tau = \vec{r} \times \vec{F}](https://tex.z-dn.net/?f=%5Ctau%20%3D%20%5Cvec%7Br%7D%20%5Ctimes%20%5Cvec%7BF%7D)
![\tau = r \times F cos \theta](https://tex.z-dn.net/?f=%5Ctau%20%3D%20r%20%5Ctimes%20F%20cos%20%5Ctheta%20)
![\tau = 0.55 \times 8 \times 9.8 \times cos 30^0](https://tex.z-dn.net/?f=%5Ctau%20%3D%200.55%20%5Ctimes%208%20%5Ctimes%209.8%20%5Ctimes%20cos%2030%5E0%20)
![\tau =37.34\ N m](https://tex.z-dn.net/?f=%5Ctau%20%3D37.34%5C%20N%20m)
torque about his shoulder join is equal to ![\tau =37.34\ N m](https://tex.z-dn.net/?f=%5Ctau%20%3D37.34%5C%20N%20m)
Answer:
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let Coefficients of Friction of Rubber on asphalt (dry) =0.7
F= Coefficients of Friction * normal force = 0.7 * 60 =42 N
so the net force of the rubber is zero, meaning it will travel at a constant speed.
When the rubber is travel at 2m/s, 42N is required to keep moving at constant speed
Answer: ok
Explanation:
The molecules in hot air are moving faster than the molecules in cold air. Because of this, the molecules in hot air tend to be further apart on average, giving hot air a lower density. That means, for the same volume of air, hot air has fewer molecules and so it weighs less.
Refer to the diagram shown below.
For horizontal equilibrium,
T₃ cos38 = T₂ cos 50
0.788 T₃ = 0.6428 T₂
T₃ = 0.8157 T₂ (1)
For vertical equilibrium,
T₂ sin 50 + T₃ sin 38 = 430
0.766 T₂ + 0.6157 T₃ = 430
1.2441 T₂ + T₃ = 698.392 (2)
Substitute (1) into (2).
(1.2441 + 0.8157) T₂ = 698.392
T₂ = 339.058 N
T₃ = 0.8157(399.058) = 276.571 N
Answer:
T₂ = 339.06 N
T₃ = 276.57 N