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sukhopar [10]
3 years ago
10

A balloon with a volume of 2.0 L at 25°C is placed

Chemistry
1 answer:
Natali5045456 [20]3 years ago
3 0

Answer:

V₂ = 2.1 L

Explanation:

Given data:

Initial volume of balloon = 2.0 L

Initial temperature = 25°C

Final temperature = 35°C

Final volume of balloon in hot room = ?

Solution:

Initial temperature = 25°C (25+273= 298 K)

Final temperature = 35°C (35+273 = 308 k)

According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume  

T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

V₂ = V₁T₂/T₁  

V₂ = 2.0 L × 308 K / 298 k

V₂ = 616 L.K / 298 K

V₂ = 2.1 L

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Vesna [10]
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Note: The value for Q was written as a negative value in the equation as heat energy was given off by the metal when the metal was cooled (from the metal’s point of view, it’s losing heat energy).
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3 years ago
Why did the plant that could not photosynthesize stop growing?
Snowcat [4.5K]

Answer:

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Explanation:

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3 years ago
If an unknown element displays many extremely strong metallic properties, where is it most likely to be located on the periodic
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3 0
3 years ago
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Is o3 inorganic or organic
sammy [17]

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6 0
3 years ago
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C3H8 + 5 O2 → 3 CO2 + 4 H2O<br> What is the number of atoms on each side of the equation?
Roman55 [17]

Answer: 1.2642*10²⁵ on both sides

Explanation:

First check how many moles are there on each side.
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There are 3 moles of carbon and 8 moles of hydrogen in C3H8
and 2 moles of oxygen in O2 but there 5 infront so 2*5 is 10
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21 Moles* (6.02*10²³)/Mol
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2 years ago
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