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sukhopar [10]
3 years ago
10

A balloon with a volume of 2.0 L at 25°C is placed

Chemistry
1 answer:
Natali5045456 [20]3 years ago
3 0

Answer:

V₂ = 2.1 L

Explanation:

Given data:

Initial volume of balloon = 2.0 L

Initial temperature = 25°C

Final temperature = 35°C

Final volume of balloon in hot room = ?

Solution:

Initial temperature = 25°C (25+273= 298 K)

Final temperature = 35°C (35+273 = 308 k)

According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume  

T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

V₂ = V₁T₂/T₁  

V₂ = 2.0 L × 308 K / 298 k

V₂ = 616 L.K / 298 K

V₂ = 2.1 L

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C (graphite) is used as a lubricant, whereas C (diamond) is used as an abrasive. Why is this?
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In contrast, most of the carbon atoms in a piece of diamond would be connected to each other. Unlike the sheets in graphite, in a diamond there are almost no moving parts. Also, the forces between neighboring carbon atoms are very strong. When an external force acts on a chunk of diamond, the carbon atoms would barely move. Hence, the structure appears to be very rigid. That gives diamond its abrasive properties.

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What is the mass, in grams, of 9.01 x 1024 molecules of methanol (CH, OH) ?
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Answer:

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Explanation:

Given data:

Number of molecules of methanol = 9.01 ×10²⁴

Mass in gram = ?

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The given problem will solve by using Avogadro number.

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Mass = 480.6 g

3 0
3 years ago
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