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Arlecino [84]
2 years ago
9

In the presence of a strong acid, litmus paper exhibits a(n) _________________ color.

Chemistry
1 answer:
tino4ka555 [31]2 years ago
3 0
The answer is blue!!!!!!
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3. You are a water molecule in the ocean and are getting ready to move through the water cycle. Please describe your journey thr
Usimov [2.4K]

Answer:

Water moves from the ground or oceans into the atmosphere through a process called evaporation. It's a process that happens on a molecular level when the molecules of water are really energized and rise into the air. Now you've got water in the air and water on land. Organisms all over the Earth need water to survive.

Explanation:

8 0
2 years ago
A chemical reaction in which compounds break up into simpler constituents is a _______ reaction.
klio [65]
C. decomposition reaction
8 0
3 years ago
From a 2.875 g sample containing only iron, sand, and salt, 0.660 g of iron and 1.161 g of sand were separated and recovered. Wh
Serjik [45]

Answer:

36.66%

Explanation:

Step 1: Given data

  • Mass of iron: 0.660 g
  • Mass of sand: 1.161 g
  • Mass of the sample: 2.875 g
  • Mass of salt: ?

Step 2: Calculate the mass of salt

The mass of the sample is equal to the sum of the masses of the components.

m(sample) = m(iron) + m(sand) + m(salt)

m(salt) = m(sample) - m(iron) - m(sand)

m(salt) = 2.875 g - 0.660 g - 1.161 g

m(salt) = 1.054 g

Step 3: Calculate the percent of salt in the sample

We will use the following expression.

%(salt) = m(salt) / m(sample) × 100%

%(salt) = 1.054 g / 2.875 g × 100% = 36.66%

7 0
3 years ago
In science test are sometime clled
natita [175]

Answer:

In the scientific method, an experiment is an empirical procedure that arbitrates competing models or hypotheses. Researchers also use experimentation to test existing theories or new hypotheses to support or disprove them

Explanation:

Hope this helps

4 0
3 years ago
Read 2 more answers
I need help with number 8 please help ASAP.
Rzqust [24]

Answer:

33.33% = 33%

Explanation:

MgCO3(s) + 2HCl (aq) --> MgCl2(aq) + H20(l) + CO2(g)

1 mole of MCO3 will produce → 1 mole of CO2

We need to get the number of mole of CO2:

and when we have 0.22 g of CO2, so number of mole = mass / molar mass

Moles = 0.22 g / 44 g/mol = 0.005 mole

Moles of Mg = moles of CO2 = 0.005 mole

Mass of Mg = moles * molar mass

= 0.005 * 84 /mol = 0.42 g

Percent of MgCO3 by mass of Mg = 0.42 g / 1.26 * 100

=33.33 %

8 0
3 years ago
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