Answer is: molality od sodium chloride is 2,55 mol/kg.
V(solution) = 100 ml.
m(solution) = d(solution) · V(solution).
m(solution) = 1,10 g/ml · 100 ml.
m(solution) = 110 g.
ω(NaCl) = 13,0% = 0,13.
m(NaCl) = ω(NaCl) · m(solution).
m(NaCl) = 0,13 · 110 g.
m(NaCl) = 14,3 g.
n(NaCl) = m(NaCl) ÷ M(NaCl).
n(NaCl) = 14,3 g ÷ 58,5 g/mol.
n(NaCl) = 0,244 mol.
m(H₂O) = 110 g - 14,3 g.
m(H₂O) = 95,7 g = 0,0957 kg.
b(NaCl) = n(NaCl) ÷ m(H₂O).
b(NaCl) = 0,244 mol ÷ 0,0957 kg.
b(NaCl) = 2,55 mol/kg.
It is 12 to 1 or 12/1 miles of saline to L solution
Answer:
D.<em> </em>Radiation
<em>Explanation:</em>
The Sun always transfers its energy to any planet (Including Earth) through <u>solar radiation, infrared, and UV rays.</u> These are all examples of <u>radiation.</u>
I hope this helps you! Good luck with your test/assignment! :D
The postulate of Dalton's atomic theory that atom is indivisible particle and can be subdivided into smaller particles was later changed because atom can be divided into neutrons, protons and electrons. It was changed because after later finding out that the atom can be divided, the theory was changed to the correct finalized theory.
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Mass of NaOH required = 12 g
<h3>Further explanation</h3>
Given
500 ml solution = 0.5 L
Molarity = 0.6 mol / L
Required
mass of NaOH
Solution
Molarity = moles of solute per liter of solution
M = n / V
solute = NaOH
moles of solute = n = M x V
n = 0.6 x 0.5
<em>n = 0.3 moles</em>
Mass of NaOH = mol x MW
mass = 0.3 x 40 = 12 g
