Answer is: 550,021 kWh of energy is needed to heat the water
V(water) = 51 gal = 51·3,78 = 189,3 L.
ΔT(water) = 25°C.
d(water) = 1000 g/L.
m(water) = V(water) · d(water)
m(water) = 189,3 L · 1000 g/L
m(water) = 189300 g.
Q = m(water) · ΔT(water) · C(water)
Q = 189300 g · 25°C · 4,184 J/°C·g
Q = 19800780 J = 19800,78 kJ ÷ 3600 = 550,021 kWh.
Answer:
Okay so set up an equation for what's happening
_C + _H + _Cl + O2 --> _CO2 + _H2O
0.451g of CO2. Convert to moles by using the molar mass of CO2 which is 44 g/mol. Now look at the ratio between Carbon and Oxygen in CO2. It's 1C:2O You just want to find C.. so do the number of moles CO2 and multiply it by 1 since the ratio says 1 carbon atom. Now you have moles of carbon. Put this number aside for later.
Do the same thing with H2O. Convert to moles by using the molar mass of H2O which is 18 g/mol. Now look at the ratio between Hydrogen and Oxygen. It's 2H:1O You just want H.. so do the number of moles of H2O and multiply it by 2 since there's 2 hydrogen atoms. Now you have the moles of hydrogen & put this number aside for later
Lastly, you need to find the chlorine. uuhhh I cant figure this part out
Explanation: ..
I hope I helped lol!
When mass Ti = density * volume
and when moles Ti = mass Ti/molar mass Ti
∴ Volume = 2.86 x 10^23 atom * ( 1 mol Ti / 6.022 x 10^23) * (47.867 g Ti / 1 mol Ti) *(1Cm3 / 4.5 g Ti )
= 5.05 Cm^3
when we assume that the sample of Ti is a cube:
and we assume the length = X
∴ V = X^3
∴X^3 = 5.05
∴X = ∛5.05
= 1.7 Cm
<span>Scientists ignore the forces of attraction between particles in a gas under ordinary conditions</span><span> because the particles in a gas are apart and moving fast, rather than clustered and moving slow, therefore the forces of attraction are too weak to have a visible effect.</span>
Answer:
No more than 0.1 mL of hydrochloricton acid
