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Svetllana [295]
3 years ago
10

Water's _____ point is _____.

Chemistry
2 answers:
Katarina [22]3 years ago
7 0
The answer is b. I hope this helps.
icang [17]3 years ago
3 0

ANSWER:

the answer is B.boiling; 100 °C

TIP: its not the others cuz for melting or freezing it would have to be a negative number!

~batmans wife dun dun dun...aka ~serenitybella

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26. Which waves have wavelengths longer than those of visible light? Give an example of how each kind
Kipish [7]

Answer:

Infrared radiation lies between the visible and microwave portions of the electromagnetic spectrum. Infrared waves have wavelengths longer than visible and shorter than microwaves, and have frequencies which are lower than visible and higher than microwaves.

Explanation:

8 0
3 years ago
Describe how Gregor mendel's methods helped endure the accuracy of his results​
aliina [53]
Not sure good luck on finding someone too help you
7 0
3 years ago
The following thermochemical equation is for the reaction of nitrogen(g) with oxygen(g) to form nitrogen dioxide(g). N2(g) + 2O2
Rzqust [24]

<u>Answer:</u> The mass of nitrogen gas reacted to produce given amount of energy is 5.99 grams.

<u>Explanation:</u>

The given chemical reaction follows:

N_2(g)+2O_2(g)\rightarrow 2NO_2(g);\Delta H=66.4kJ

We know that:

Molar mass of nitrogen gas = 28 g/mol

We are given:

Enthalpy change of the reaction = 14.2 kJ

To calculate the mass of nitrogen gas reacted, we use unitary method:

When enthalpy change of the reaction is 66.4 kJ, the mass of nitrogen gas reacted is 28 grams.

So, when enthalpy change of the reaction is 14.2 kJ, the mass of nitrogen gas reacted will be = \frac{28}{66.4}\times 14.2=5.99g

Hence, the mass of nitrogen gas reacted to produce given amount of energy is 5.99 grams.

8 0
4 years ago
Help please Chemistry
dybincka [34]

Answer:Cant see the picture cause its too big

Explanation:

7 0
3 years ago
How many grams of oxygen are required too burn 8.8g of c3h8?
hichkok12 [17]
From the balanced equation: 
<span>1mol C3H8 requires 5mol O2 for combustion </span>
<span>Molar mass C3H8 = 44g/mol </span>
<span>8.8g C3H8 = 8.8/44 = 0.2mol C3H8 </span>
<span>This will require 5*0.2 = 1.0mol O2 </span>
<span>Molar mass O2 = 32g/mol </span>
<span>Therefore 32g of O2 required.


</span>
4 0
3 years ago
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