Answer:
at 181.0 
is -723.3 kJ/mol.
Explanation:
We know, 
where, T is temperature in kelvin.
Let's assume 
and 
does not change in the temperature range 25.0 - 181.0 .
= (273+181.0) K = 454.0 K
Hence, at 181.0 , ![\Delta G^{0}=(-795.8kJ/mol)-[(454.0 K)\times (-159.8\times 10^{-3}kJ/K.mol)]](https://tex.z-dn.net/?f=%5CDelta%20G%5E%7B0%7D%3D%28-795.8kJ%2Fmol%29-%5B%28454.0%20K%29%5Ctimes%20%28-159.8%5Ctimes%2010%5E%7B-3%7DkJ%2FK.mol%29%5D)
= -723.3 kJ/mol
Answer:
1
Explanation:
For an ideal gas, the average kinetic energy is given by:
Ek = (3/2)*n*R*T
Where n is the number of moles, R is the gas constant (8.31 J/mol*K), and T the temperature. The gases have the same number of moles, and the same temperature, so they will have the same average kinetic energy:
Ek = (3/2)*1*8.31*300
Ek =3739.5 J
So, the ratio between then is 1.
The equilibrium constant of the reaction is 282. Option D
<h3>What is equilibrium constant?</h3>
The term equilibrium constant refers to the number that often depict how much the process is able to turn the reactants in to products. In other words, if the reactants are readily turned into products, then it follows that the equilibrium constant will be large and positive.
Concentration of bromine = 0.600 mol /1.000-L = 0.600 M
Concentration of iodine = 1.600 mol/1.000-L = 1.600M
In this case, we must set up the ICE table as shown;
Br2(g) + I2(g) ↔ 2IBr(g)
I 0.6 1.6 0
C -x -x +2x
E 0.6 - x 1.6 - x 1.190
If 2x = 1.190
x = 1.190/2
x = 0.595
The concentrations at equilibrium are;
[Br2] = 0.6 - 0.595 = 0.005
[I2] = 1.6 - 0.595 = 1.005
Hence;
Kc = [IBr]^2/[Br2] [I2]
Kc = ( 1.190)^2/(0.005) (1.005)
Kc = 282
Learn more about equilibrium constant:brainly.com/question/15118952
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The SI unit for amount<span> of </span>substance<span> is the </span>mole<span>. It has the unit symbol mol. The proportionality constant is the inverse of the Avogadro constant. The </span>mole<span> is defined as the </span>amount<span> of </span>substance that contains<span> an equal </span>number<span> of elementary entities as there are </span>atoms in 12g<span> of the </span>isotope<span> carbon-</span>12<span>.
Hope This Helped! :3</span>
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