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MatroZZZ [7]
3 years ago
5

In a molecule of calcium sulfide, calcium has two valence electron bonds, and a sulfur atom has six valence electrons. How many

lone pairs of electrons are present in the Lewis structure of calcium sulfide?
A. one
B. two
C. three
D. four
E. none
Also, state why.
Chemistry
1 answer:
mote1985 [20]3 years ago
7 0

There are none

<h3>Further explanation</h3>

Given

a molecule of calcium sulfide

two valence electron of Calcium(Ca)

six valence electrons of Sulfur(S)

Required

number of lone pairs of electrons

Solution

Lewis structure shows the form of bonds that occur in the valence electrons of an element or compound

Valence electrons are electrons used in a chemical bond

To achieve stability, the element S needs 2 more electrons which are obtained from 2 electrons from the Ca element,

A lone pair electron means refers to an unshared pair of electrons(not bonding to the other atoms)

This condition usually occurs in covalent bonds

As we know, the bond between Ca, which is a group 2 (metal) with Sulfur in group 16, is an ionic bond because it occurs between metal and non-metal ions, so there is no sharing of electrons, but there is a release of electrons from Ca ions to S ions to form an octet. , so all the valence electrons in S are paired

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jeka57 [31]

Answer:

The molecular formula of glucose is C₆H₁₂O₆

Explanation:

Empirical formula:

It is the simplest formula gives the ratio of smallest whole number of atoms.

Molecular formula:

It gives the total number of atoms in a molecule of compound.

The molecular formula and empirical formula can be related as follow:

Molecular formula = n × empirical formula

Given data:

Empirical formula = CH₂O

Molecular formula = ?

It is stated in given problem that molecular formula is the 6 times of the empirical formula.

Molecular formula = n × empirical formula

Molecular formula = 6 × CH₂O

Molecular formula = C₆H₁₂O₆

The molecular formula of glucose is C₆H₁₂O₆.

5 0
3 years ago
(Please someone help me!) (No links!)
andreyandreev [35.5K]

Answer:

you picked the right one the net worth of force would be 10

Explanation:

how cuz you got 1 team with 6 force then aother 1 with 4 add em up u get 10

3 0
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Calculate the molality of an ethylene glycol (C2H6O2) soltuion, that has a molarity of 2.07 M. The density of the solution is 1.
vlada-n [284]

Answer:

2.03

Explanation:

Let's <u>assume we have 1 L of the solution</u>:

  • There would be 2.07 ethylene glycol moles.
  • The solution would weigh (1000 mL * 1.02 g/mL) = 1020 g.

With that information we can <u>calculate the molality</u>:

  • molality = moles of solute / kg of solvent
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3 0
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a researcher obtains a sample of 0.070 M nitrate solition. A 20.0 mL aliquote of the nitrate solution is added to 10.0 mL of amm
katovenus [111]

Answer:

Concentration of nitrate in the new solution = 0.007 M

Explanation:

Given:

Concentration nitrate solution = 0.070 m

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Find:

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Concentration of nitrate in the new solution = 0.007 M

6 0
2 years ago
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