Answer:
The number of expected people at the concert is 8,500 people
Step-by-step explanation:
In this question, we are asked to determine the expected number of people that will attend a concert if we are given the probabilities that it will rain and it will not rain.
We proceed as follows;
The probability that it will rain is 30% or 0:3
The probability that it will not rain would be 1 -0.3 = 0.7
Now, we proceed to calculate the number of people that will attend by multiplying the probabilities by the expected number of people when it rains and when it does not rain.
Mathematically this is;
Number of expected guests = (probability of not raining * number of expected guests when it does not rain) + (probability of raining * number of expected guests when it rains)
Let’s plug values;
Number of expected guests = (0.3 * 5,000) + (0.7 * 10,000) = 1,500 + 7,000 = 8,500 people
-2.38 is the answer because 7x-3.4=x/10=-2.38
Answer:
16
Step-by-step explanation:
If
, just put the number
instead of
.
So:
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Answer:
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
Step-by-step explanation:
Given the system of the equations
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solving by elimination method








solve
for
:




Solve
for x:



Therefore,
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5^4 * 5^(-6) * 5
= 5^4 * 5^(-6) * 5^1
= 5^[ 4 + (-6) + 1 ]
= 5^[ 4 - 6 + 1 ]
= 5^(-1) <----- this is the answer.
I hope this helps. =)