To solve this we use the equation,
<span>M1V1 = M2V2</span>
<span>where M1 is the concentration of the stock
solution, V1 is the volume of the stock solution, M2 is the concentration of
the new solution and V2 is its volume.</span>
0.25<span> M x V1 = 0.15 M x .500 L</span>
<span>
V1 = 0.3 L or 300 mL</span>
Answer:
0.88g
Explanation:
The reaction equation:
2NaI + Cl₂ → 2NaCl + I₂
Given parameters:
Mass of Sodium iodide = 2.29g
Unknown:
Mass of NaCl = ?
Solution:
To solve this problem, we work from the known to the unknown.
First find the number of NaI from the mass given;
Number of moles =
Molar mass of NaI = 23 + 126.9 = 149.9g/mol
Now insert the parameters and solve;
Number of moles =
= 0.015mol
So;
From the balanced reaction equation;
2 moles of NaI produced 2 moles of NaCl
0.015mole of NaI will produce 0.015mole of NaCl
Therefore;
Mass = number of moles x molar mass
Molar mass of NaCl = 23 + 35.5 = 58.5g/mol
Now;
Mass of NaCl = 0.015 x 58.5 = 0.88g
MgF is an ionic compound because it's bond is between a metal and a non-metal
Explanation:
We have 2CO + O2 => 2CO2.
Moles of CO = 28.6g / (28g/mol) = 1.021mol.
Moles of CO2 = Moles of CO = 1.021mol.
No. of moles -= given mass/ molar mass
1) 9 g of H2O = 9/18 = 1/2 = 0.5 mole
2) 88g of CO2 = 88/44 = 2moles
3) 1.7 g of NH3 = 1.7/17 = 0.1 mole