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3 years ago

What type of plate boundary do most volcanoes occur along

Physics

1 answer:

sertanlavr [38]3 years ago

6 0

Answer:

Subducting convergent boundary

Explanation:

Generally, volcanoes occurs in both divergent and convergent boundaries. But the convergent boundary it occurs is usually associated with subduction.

Divergent boundary, plates move away from each other creating a new crust in the process. The diverging plates creates the space for magma to be squeezed through cracks and fissures. The magma's erupt to form volcanoes. In the Atlantic ocean the spreading of the plates causes an upwelling of magma through the crest of the Atlantic ridges. New oceanic crust are formed through this process. Sometimes the magma eruption forms volcanoes that are higher than the sea level.

Convergent boundary , plates collides with each other . But in the case of volcanoes existence , the collision should be between a denser plate(oceanic plates) and a less dense plates(continental plates) so that subduction can take place. The subducted plates (oceanic plates) creates trenches and get expose to high temperature and pressure as it sinks toward the mantle. The upper mantle rocks melts and migrate to the earth surface forming volcanoes . Over 75% of the volcanoes occur along the pacific basin where convergent boundary is dominant. Pacific ring of fire has one of the most number of volcanoes.

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Jane is a crime scene investigator. She wants to reveal small particles with high contrast. So, she positions the forensic lamp

qwelly [4]

Answer:

Pretty sure it's B. Oblique Lighting

Explanation:

A. is clearly wrong, C. is also clearly wrong, D and E both have nothing to do with lighting, Oblique Lighting is defined as "using a light source positioned at a low angle. Oblique lighting is usually used to show detail by creating shadows on the surface of the evidence." Hope this helps.

6 0

3 years ago

You have a ball with a mass 1.3 kg tied to a rope, and you spin it in a circle of radius 1.8m. If the ball is moving at a speed

BlackZzzverrR [31]

Answer:

$6.5\; {\rm N}$ .

Explanation:

When an object travel at a speed of $v$ in a circle of radius $r$ , the (centripetal) acceleration of that object would be $a = (v^{2} / r)$ .

In this question, the ball is travelling at $v = 3\; {\rm m\cdot s^{-1}}$ in a circle of radius $r = 1.8\; {\rm m}$ . The (centripetal) acceleration of this ball would be:

$\begin{aligned} a &= \frac{v^{2}}{r} \\ &= \frac{(3\; {\rm m\cdot s^{-1}})^{2}}{1.8\; {\rm m}} \\ &= 5\; {\rm m\cdot s^{-2}}\end{aligned}$ .

By Newton's Laws of Motion, for an object of mass $m$ , if the acceleration of that object is $a$ , the net force on that object would be $m\, a$ . Since the acceleration of this ball is $a = 5\; {\rm m\cdot s^{-2}}$ , the net force on this ball would be:

$\begin{aligned} F &= m\, a \\ &= 1.3\; {\rm kg} \times 5\; {\rm m\cdot s^{-2}} \\ &= 6.5\; {\rm N} \end{aligned}$ .

7 0

2 years ago

a 64kg skateboarder on a 2.0kg skateboard is on top of a ramp with a vertical height of 5.0 m what is the skateboarders maximum

WITCHER [35]

The formula for a kinetic energy KE of a falling body is
KE = mgh
where m = mass, g = acceleration due to gravity (9.8 m/s^2, constant), h = height.

The total mass of a skateboader and a skateboard is 64 + 2.0 = 66 kg.

Finally,
KE = 66*9.8*5.0 = 32340 J

7 0

3 years ago

How does the north pole of a magnet respond to the poles of other magnets?

tensa zangetsu [6.8K]

Answer:

Explanation:

A magnet has a magnetic field around it which originates at the north pole and enters through the south pole.

In a magnet, like poles will repel each other and unlike poles will attract.

The north pole of one magnet will repel another north pole of another magnet.
North pole of one magnet will attract the south pole of another magnet.
This is the law of attraction and repulsion of magnet.

8 0

3 years ago

Read 2 more answers

From the gravitational law calculate the weight W (gravitational force with respect to the earth) of a 89-kg man in a spacecraft

zhannawk [14.2K]

Answer:

$W=\frac{773}{4.45}=173.76 l b f$

Explanation:

$W=\frac{G \cdot m_{e} \cdot m}{(R+h)^{2}}$

The law of gravitation

$G=6.673\left(10^{-11}\right) m^{3} /\left(k g \cdot s^{2}\right)$

Universal gravitational constant [S.I. units]

$m_{e}=5.976\left(10^{24}\right) k g$

Mass of Earth [S.I. units]

$m=89 kg$

Mass of a man in a spacecraft [S.I. units]

$R=6371 \mathrm{~km}$

Earth radius [km]

Distance between man and the earth's surface

$h=261 \mathrm{~km} \quad[\mathrm{~km}]$

ESULT $W=\frac{6.673\left(10^{-11}\right) \cdot 5.976\left(10^{24}\right) \cdot 89}{\left(6371 \cdot 10^{3}+261 \cdot 10^{3}\right)^{2}}=773.22 \mathrm{~N}$

$W=\frac{773}{4.45}=173.76 l b f$

4 0

2 years ago