Answer: I am pretty sure the answer is B
Explanation: If not sorry bro.
I don’t think we can answer this question with the information given. ANY ball thrown with ANY initial velocity v will be observed at a height h twice and with a time interval Δt.
Answer:
1.8 m/s
Explanation:
momentum = mass × velocity
initial momentum = m1v1+m2v2
= 3×3 +2×0 = 9+0= 9 kg m/s
let combined velocity be V
HENCE
final momentum = total mass × velocity
= (3+2) × V = 5V
According to law of conservation of momentum
final momentum = initial momentum
5V = 9
V =9/5
V = 1.8 m/s
Answer:
50,000 V/m
Explanation:
The electric field between two charged metal plates is uniform.
The relationship between potential difference and electric field strength for a uniform field is given by the equation
where
is the potential difference
E is the magnitude of the electric field
d is the distance between the plates
In this problem, we have:
is the potential difference between the plates
d = 15 mm = 0.015 m is the distance between the plates
Therefore, rearranging the equation we find the strength of the electric field:
