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3 years ago

What happens during the apparent retrograde motion of a planet?

Physics

1 answer:

anygoal [31]3 years ago

6 0

Answer:

The planet will move from east to west for a couple of months in the night sky.

Explanation:

Retrograde motion is an optical effect due to the fact that Earth rotates more quickly than the planet that apparently has a retrograde motion in the sky.

For example, Saturn has a slower speed in its orbit around the Sun. That means that the Earth will pass it, and that will give the effect that the planet is moving backward. That same scenario can be seen between two cars on a highway, the faster car will see the slower car when it passes as it is moving for a short fragment of time in backward.

Remember that the planets in the night sky move from west to east, in the case of a planet with retrograde motion, it will move from east to west for a couple of months.

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Which type of force is changing the object's speed and direction when a toy clown pops out of a jack-in-the-box?

Murrr4er [49]

I think it would be d because the spring or whatever was pushing until it reached the farthest it could then it would pull down but idrk

3 0

3 years ago

Read 2 more answers

3<br> What is happening in this graph from point B to C?

neonofarm [45]

You have a photo? I could help you if you show me a picture!

8 0

3 years ago

To stop a car, first you require a certain reaction time to begin braking; then the car slows under the constant braking deceler

ANEK [815]

Answer:

a) $t_r = 0.55 s$

b) a = 5.59 m/s²

Explanation:

given,

total distance traveled by the car to stop is 56.9 m when speed of vehicle is 80 km/h or 80 × 0.278 = 22.24 m/s

total distance traveled by the car to stop is 25.7 m when speed of vehicle is 50.7 km/h or 50.7 × 0.278 = 14.09 m/s

using stopping distance formula

$s_1 = v_1 t_r +\dfrac{v_1^2}{2 a}$ ................(1)

$s_2 = v_2 t_r +\dfrac{v_2^2}{2 a}$ ..............(2)

on solving both the equation we get

$a = \dfarc{v_1v_2(v_1-v_2)}{2(s_1v_2-s_2v_1)}$

$a = \dfarc{22.4\times 14.09(22.24-14.09)}{2(56.9\times 14.09-25.7\times 22.24)}$

a = 5.59 m/s²

now reaction time calculation

$t_r =\dfrac{v_1^2d_2-v_2^2d_1}{v_1v_2(v_1-v_2)}$

$t_r =\dfrac{22.24^2\times 25.7-14.09^2\times 56.9}{22.4\times 14.09(22.24-14.09)}$

$t_r = 0.55 s$

8 0

3 years ago

A 2.45 cm tall object is placed in 33.7 cm in front of a convex lens. The focal length

timofeeve [1]

Answer:

-1.65

Explanation:

First of all, we find the position of the image by using the lens equation:

$\frac{1}{f}=\frac{1}{p}+\frac{1}{q}$

where:

f is the focal length of the lens

p is the distance of the object from the lens

q is the distance of the image from the lens

For the lens in this problem:

f = 21.0 cm (the focal length of a convex lens is positive)

p = 33.7 cm

Solving for q, we find the position of the image:

$\frac{1}{q}=\frac{1}{f}-\frac{1}{p}=\frac{1}{21.0}-\frac{1}{33.7}=0.0179 cm^{-1}\\q=\frac{1}{0.0179}=55.7 cm$

Then, the magnification of the image is given by:

$M=-\frac{q}{p}$

And substituting,

$M=-\frac{55.7}{33.7}=-1.65$

Which means that the image is inverted (negative sign) and enlarged (because M is larger than 1).

3 0

3 years ago

From t=0 onwards what happens to the voltage across the inductor annd the curreent through the inductor relative to their values

gregori [183]

From t=0 onwards I changes slowly and V changes abruptly across the inductor.

At time t=0, the voltage across the inductor equalises the battery voltage; nevertheless, Lenz's Law states that this induced EMF will always be opposed to the polarity of the battery. The voltage across the inductor is equivalent to the voltage of a battery because the inductor at time zero behaves like a second battery of the same voltage linked in reverse.

Because current can never be zero, voltage across the inductor decreases with time. If it did, there would be no back EMF to stop the current from flowing through the inductor because the magnetic field would not be changing. As a result, the inductor will become less of an open circuit as the current increases over time. The inductor will essentially behave like a resistor.

Learn more about inductor here:

brainly.com/question/15893850

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3 0

2 years ago