Newtons first law is that an Object that is in motion will stay in motion until an unbalanced force acts upon it, and part 2 is that an object at rest will stay at rest until and unbalanced force acts upon it
Answer: 2500km/s
Explanation:
use equation wich conects distance and acceleration:
S=Vst+at²/2
Vs=0km/s(from rest)
S=at²/2
S2=at²
t=√2S/a
t=√2*125km/25000 km/s²
t=0.1s
Vf --final velocity
Vs-- start velocity
a=Vf-Vs/t
at=Vf-Vs
Vs=0Km/s
at=Vf
25000Km/s*0.1s=Vf
Vf=2500Km/s
Answer:
The horizontal distance the pumpkin will travel after it slips from the eagle is 17.02 m
Explanation:
Given;
height above the ground, h = 16.4 m
speed of the eagle, v = 9.3 m/s
The time it will take the pumpkin to fall at the given height is calculated as;

The horizontal distance traveled at this time is given by;
x = vt
x = (9.3)(1.83)
x = 17.02 m
Therefore, the horizontal distance the pumpkin will travel after it slips from the eagle is 17.02 m
Answer: 1.2 s
It is given that a ball is thrown vertically upwards with initial velocity, u= 12 m/s.
At the maximum height, instantaneous velocity would be, v= 0 m/s
the ball would decelerate due to gravity, 
using equation of motion,

Hence, the time taken by ball to reach its maximum height is 1.2 s when thrown vertically upward with initial velocity of 12 m/s.