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alexdok [17]
1 year ago
7

consider a different titrant for this exercise. suppose ca(oh)2 were used as the titrant, instead of naoh. this will make the ti

trant twice as concentrated in hydroxide ion. the analyte will still be hc2h3o2. (a) what is the stoichiometry of hc2h3o2 to ca(oh)2?
Chemistry
1 answer:
Ivan1 year ago
4 0

The titrant for this exercise. suppose Ca(OH)₂ were used as the titrant, instead of NaOH. This will make the titrant twice as concentrated in hydroxide ion. the analyte will still be HC₂H₃O₂. the stoichiometry ratio of  HC₂H₃O₂ to Ca(OH)₂ is 1 : 2.

The balanced reaction of the given condition as follow :

 Ca(OH)₂   +      2HC₂H₃O₂      ------>     Ca(C₂H₃O₂)₂     +    2H₂O

from the equation it is clear that stoichiometry of Ca(OH)₂ is 1 and the stoichiometry of HC₂H₃O₂    is 2. therefore the stoichiometry ratio of  HC₂H₃O₂ to Ca(OH)₂ is 1 : 2.

Thus, The titrant for this exercise. suppose Ca(OH)₂ were used as the titrant, instead of NaOH. This will make the titrant twice as concentrated in hydroxide ion. the analyte will still be HC₂H₃O₂. the stoichiometry ratio of  HC₂H₃O₂ to Ca(OH)₂ is 1 : 2.

To learn more about stoichiometry here

brainly.com/question/13145466

#SPJ4

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V KOH = 41 mL

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for neutralization:

  • ( V×<em>C </em>)acid = ( V×<em>C </em>)base

∴ <em>C </em>H2SO4 = 0.0050 M = 0.0050 mol/L

∴ V H2SO4 = 41 mL = 0.041 L

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∴ E KOH = 1 eq-g/mol

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