All categories

3 years ago

What is true when a reaction has reached equilibrium?

Chemistry

1 answer:

KATRIN_1 [288]3 years ago

3 0

Answer:

The concentration of the products and reactants is constant.

Explanation:

Once the reversible reaction that proceeds forward and backward simultaneously has reached it's state of chemical equlibrium, the concentration of products and reactants become constant.

This means that the rate at which the reactants react to form products becomes equal to the rate at which products react to form the reactants again. At this point there will be no further change in the concentration of reactants and products with time. In chemical equilibrium the concentration of a reactant or a product is expressed in moles per cubic decimeter ( mol / dm^3.

You might be interested in

HelpUsing a 2-cm-thick piece of cardboard over a radiation source would be mosteffective for protecting against which type of ra

Lisa [10]

It would protect best against C) Alpha radiation, as Beta radiation is stopped by lighter metals such as aluminium, and Gamma radiation can only be stopped by heavier metals such as lead.

3 0

3 years ago

Read 2 more answers

Explain the law of conservation of energy.

Ulleksa [173]

<h2>Energy is conserved. It never appears or disappears. It just changes from one kind of type to another. The Universe contains the same amount of energy it started with. This amount can never change.</h2><h2></h2>

6 0

3 years ago

Read 2 more answers

How could a blizzard affect a rabbit?

zloy xaker [14]

The rabbit could die

8 0

3 years ago

Atoms of which element have two protons and two electrons?

Len [333]

B.) Helium have <span>two protons and two electrons

Hope this helps!</span>

6 0

2 years ago

Read 2 more answers

Determine total H for bonds broken and formed, the overall change in H, and the final answer with units. Is it ENDOthermic or EX

Mrac [35]

E(Bonds broken) = 1371 kJ/mol reaction
E(Bonds formed) = 1852 kJ/mol reaction

ΔH = -481 kJ/mol.
The reaction is exothermic.

<h3>Explanation</h3>

2 H-H + O=O → 2 H-O-H

There are two moles of H-H bonds and one mole of O=O bonds in one mole of reactants. All of them will break in the reaction. That will absorb

E(Bonds broken) = 2 × 436 + 499 = 1371 kJ/mol reaction.
ΔH(Breaking bonds) = +1371 kJ/mol

Each mole of the reaction will form two moles of water molecules. Each mole of H₂O molecules have two moles O-H bonds. Two moles of the molecule will have four moles of O-H bonds. Forming all those bond will release

E(Bonds formed) = 2 × 2 × 463 = 1852 kJ/mol reaction.
ΔH(Forming bonds) = - 1852 kJ/mol

Heat of the reaction:

$\Delta H_{\text{rxn}} = \Delta H(\text{Breaking bonds}) + \Delta H(\text{Forming bonds})\\\phantom{ \Delta H_{\text{rxn}}} = +1371 + (-1852) \\\phantom{ \Delta H_{\text{rxn}}} = -481 \; \text{kJ} / \text{mol}$

$\Delta H_{\text{rxn}}$ is negative. As a result, the reaction is exothermic.

3 0

3 years ago