Answer:
Explanation:
The sun is made up of 6 parts. Namely:
- The core
- The radiation zone
- The convection zone
- The photosphere
- The chromosphere and
- The corona
The convection area is just above the radiation zone. As materials from the suns core are heated, they rise above the radiation zone towards the EDGE of the convection area then sinks back again into the radiative zone for more heat.
The radiative zone is 12.6 million Fahrenheit hot and is just above the core.
The core of the son is not solid but plasma whose motion is like gas. Its temperature stands at 48 million Fahrenheit
Cheers
False
Balanced forces mean that there is no net force acting on the object. therefore, the object will not accelerate.
Part a
Answer: NO
We need to calculate the distance traveled once the brakes are applied. Then we would compare the distance traveled and distance of the barrier.
Using the second equation of motion:

where s is the distance traveled, u is the initial velocity, t is the time taken and a is the acceleration.
It is given that, u=86.0 km/h=23.9 m/s, t=0.75 s, 

Since there is sufficient distance between position where car would stop and the barrier, the car would not hit it.
Part b
Answer: 29.6 m/s
The maximum distance that car can travel is 
The acceleration is same, 
The final velocity, v=0
Using the third equation of motion, we can find the maximum initial velocity for car to not hit the barrier:

Hence, the maximum speed at which car can travel and not hit the barrier is 29.6 m/s.
The initial speed of the vehicle before the collision is 8 m/s.
- Let the mass of the vehicle = m
- Let the initial speed of the vehicle stopped = u
- The initial speed of the vehicle parked at the red light = 0
<h3>Principle of conservation of linear momentum</h3>
- The initial speed of the vehicle before the collision is calculated by applying principle of conservation of linear momentum as follows;

Thus, the initial speed of the vehicle before the collision is 8 m/s.
Learn more about inelastic collision here: brainly.com/question/7694106
Answer:
60 Ω
Explanation:
R(com) = 15 Ω
1/R(com) = 1/R1 + 1/R2 + 1/R3 ..... + 1/Rn
1/15 = 1/20 + 1/R2
1/R2 = 1/15 - 1/20
1/R2 = (4 - 3) / 60
1/R2 = 1/60
R2 = 60 Ω
así, la combinada de resistencia necesaria es 60 Ω