Answer:
1.33 atm
Explanation:
use general gas equation P1 V1/ T1 = P2 V2/ T2
rearrange and make P2 the subject then solve,it should give you 1.33 atm
HCI is one of the most common acids out of the following
Answer:
![\%\ Error = 21.5\%](https://tex.z-dn.net/?f=%5C%25%5C%20Error%20%3D%2021.5%5C%25)
Explanation:
Given
![Measured = 24.5](https://tex.z-dn.net/?f=Measured%20%3D%2024.5)
![Actual = 31.2](https://tex.z-dn.net/?f=Actual%20%3D%2031.2)
Required
Determine the percentage error
First, we need to determine the difference in the measurement
![Difference = |Actual - Measured|](https://tex.z-dn.net/?f=Difference%20%3D%20%7CActual%20-%20Measured%7C)
![Difference = |31.2 - 24.5|](https://tex.z-dn.net/?f=Difference%20%3D%20%7C31.2%20-%2024.5%7C)
![Difference = |6.7|](https://tex.z-dn.net/?f=Difference%20%3D%20%7C6.7%7C)
![Difference = 6.7](https://tex.z-dn.net/?f=Difference%20%3D%206.7)
The percentage error is calculated as thus:
![\%\ Error = \frac{Difference * 100\%}{Actual}](https://tex.z-dn.net/?f=%5C%25%5C%20Error%20%3D%20%5Cfrac%7BDifference%20%2A%20100%5C%25%7D%7BActual%7D)
![\%\ Error = \frac{6.7 * 100\%}{31.2}](https://tex.z-dn.net/?f=%5C%25%5C%20Error%20%3D%20%5Cfrac%7B6.7%20%2A%20100%5C%25%7D%7B31.2%7D)
![\%\ Error = \frac{670\%}{31.2}](https://tex.z-dn.net/?f=%5C%25%5C%20Error%20%3D%20%5Cfrac%7B670%5C%25%7D%7B31.2%7D)
![\%\ Error = 21.4743589744\%](https://tex.z-dn.net/?f=%5C%25%5C%20Error%20%3D%2021.4743589744%5C%25)
<em>approximated</em>
I think the correct answer would be HCl + NaHCO3 -> NaCl + H2O + CO2, 2HCl + CaCO3 -> CaCl2 + CO2 + H2O, 2HCl + Mg(OH)2 -> MgCl2 + 2H2O. Hydrochloic acid would react with the basic substances in the stomach which are magnesium hydroxide, sodium bicarbonate and <span>calcium carbonate.</span>