Answer:
A covalent bond
Explanation:
the atoms bond by sharing electrons. Covalent bonds usually occur between nonmetals. For example, in water (H2O) each hydrogen (H) and oxygen (O) share a pair of electrons to make a molecule of two hydrogen atoms single bonded to a single oxygen atom.
Atoms, the main constituents of matter, consist of positively charged protons and neutral neutrons within a nucleus which are surrounded by a sea of electrons that sit in distinct shells. The electrons on the outer shell are known as valence electrons. The valence can be descibed as the smaller number of electrons an atom has to borrow or to lend, the greater the activity.
The answer is B.
Answer:
Explanation:Given;
applied force, F = 8000 N
time of force application, t = 15 s
Work done is given as the product of force and displacement. Since the car is unable to move, then the displacement is zero and the work done is zero.
Work done = Force x displacement
Work done = 8000 N x 0
Work done = 0
Therefore, the work done is zero.
Answer:
P₂ = 3.61 atm
Explanation:
Given data:
Initial pressure of tank = 3.20 atm
Initial temperature = 22.0°C
Final temperature = 60.0°C
Final pressure = ?
Solution:
Initial temperature = 22.0°C (22.0 +273 = 295 K)
Final temperature = 60.0°C (60 +273 = 333)
According to Gay-Lussac Law,
The pressure of given amount of a gas is directly proportional to its temperature at constant volume and number of moles.
Mathematical relationship:
P₁/T₁ = P₂/T₂
Now we will put the values in formula:
3.20 atm / 295 K = P₂/333 K
P₂ = 3.20 atm × 333 K / 295 K
P₂ = 1065.6 atm. K /295 K
P₂ = 3.61 atm
<u>Answer:</u> From the given gases, the greatest rate of effusion is of 
<u>Explanation:</u>
Rate of effusion of a gas is determined by a law known as Graham's Law.
This law states that the rate of effusion or diffusion of a gas is inversely proportional to the square root of the molar mass of the gas. The equation given by this law follows:
It is visible that molar mass is inversely related to rate of effusion. So, the gas having lowest molar mass will have the highest rate of effusion.
For the given gases:
Molar mass of 
Molar mass of 
Molar mass of 
Molar mass of 
Molar mass of 
The molar mass of methane gas is the lowest. Thus, it will have the greatest rate of effusion.
Hence, the greatest rate of effusion is of
