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3 years ago

Find the mass of a table that has a density of 2.35 g/cm3 and a volume of 12cm3.

Chemistry

1 answer:

Hunter-Best [27]3 years ago

8 0

Answer:

<h2>The answer is 28.2 g</h2>

Explanation:

The mass of a substance when given the density and volume can be found by using the formula

<h3>mass = Density × volume</h3>

From the question

volume of table = 12 cm³

density = 2.35 g/cm³

The mass of the table is

mass = 2.35 × 12

We have the final answer as

Hope this helps you

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A mixture containing nitrogen and hydrogen weighs 3.49 g and occupies a volume of 7.45 L at 305 K and 1.03 atm. Calculate the ma

-BARSIC- [3]

Answer:

Mass percent N₂ = 89%

Mass percent H₂ = 11%

Explanation:

First we <u>use PV=nRT to calculate n</u>, which is the total number of moles of nitrogen and hydrogen:

1.03 atm * 7.45 L = n * 0.082 atm·L·mol⁻¹·K⁻¹ * 305 K

n = 0.307 mol

So now we know that

MolH₂ + MolN₂ = 0.307 mol

and

MolH₂ * 2 g/mol + MolN₂ * 28 g/mol = 3.49 g

So we have a <u>system of two equations and two unknowns</u>. We use algebra to solve it:

Express MolH₂ in terms of MolN₂:

MolH₂ + MolN₂ = 0.307 mol

MolH₂ = 0.307 - MolN₂

Replace that value in the second equation:

MolH₂ * 2 g/mol + MolN₂ * 28 g/mol = 3.49

(0.307-MolN₂) * 2 + MolN₂ * 28 = 3.49

0.614 - 2MolN₂ + 28molN₂ = 3.49

0.614 + 26MolN₂ = 3.49

MolN₂ = 0.111 mol

Now we calculate MolH₂:

MolH₂ + MolN₂ = 0.307 mol

MolH₂ + 0.111 = 0.307

MolH₂ = 0.196 mol

Finally, we convert each of those mol numbers to mass, to <u>calculate the mass percent</u>:

N₂ ⇒ 0.111 mol * 28 g/mol = 3.108 g N₂

H₂ ⇒ 0.196 mol * 2 g/mol = 0.392 g H₂

Mass % N₂ = 3.108/3.49 * 100% = 89.05% ≅ 89%

Mass % H₂ = 0.392/3.49 * 100% = 11.15% ≅ 11%

5 0

3 years ago

The density of whole blood is 1.05 g/ml. a typical adult has between 4.7 and 5.5 l of whole blood. what is the mass in pounds of

Kisachek [45]

<span>1.05 g/ml * 1000 ml = 1050g/l because of 1g/ml = 1 kg/l so, a/q mass of 4.7 l of whole blood in pound = 4.7 * 1050 = 4935 g so in pound 4935g = 10.87981p</span>

5 0

3 years ago

Draw a schematic of the hydrogen atom with the single proton in the nucleus, and the n=1, n=2, n=3, and n=4 energy level options

max2010maxim [7]

Explanation:

According to Bohr's postulates, the electron in the present in the lower energy level can absorb energy and exits to higher energy level. Also, when this electron returns back to its orbit, it emits some energy.

Since the hydrogen consists of 1 electron and 1 proton. The lowest energy configuration of the hydrogen is when n =1 or, when the electron is present in the K-shell or the ground state.

The possible transition for the electron given in the question is :

n = 2, 3 and 4

The schematic diagram of the hydrogen atom consisting of these four quantum levels in which the electron can jump (Absorption) and comeback to from these energy levels (emission) .