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2 years ago

Which landscape will erode more quickly? Assume the same precipitation and average temperature in each landscape.

Physics

1 answer:

Artemon [7]2 years ago

5 0

Answer:

B. Landscape B

Explanation:

Shale is fine sediment pressed together to form rock.

Sandstone is larger (sand-grain-sized) sediment cemented together to form rock.

Shale erodes faster, as evidenced by the second attachment. That attachment shows erosion of a rock face consisting of interbedded shale and sandstone. The shale has receded significantly, leaving the sandstone layers with space between them.

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Given a force of 100 N and acceleration of 5 m/s2, what is the mass

tatyana61 [14]

Answer:

20 kg

Explanation:

remember the equation f=ma.

100 N=force

5 m/s2= acceleration

so you need to divide force by acceleration: 100 N/ 5 m/s2= 20 kg, to get the mass.

8 0

2 years ago

Siven an element's atomic number and mass number, how can you tell the number of protons and neutrons in its nucleus?

sukhopar [10]

It would be the first option.

Explanation-
The number of protons is equal to the atomic number the number of neutrons is the mass minus the atomic number.

3 0

2 years ago

Read 2 more answers

The compound magnesium phosphate has the chemical formula Mg3(PO4)2. In this compound, phosphorous and oxygen act together as on

zepelin [54]

The 2 means there are two phosphate ions in a molecule of magnesium phosphate.

8 0

2 years ago

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A satellite moves in a circular orbit at a constant speed v0 around Earth at a distance R from its center. The force exerted on

postnew [5]

Answer:

vT = v0/3

Explanation:

The gravitational force on the satellite with speed v0 at distance R is F = GMm/R². This is also equal to the centripetal force on the satellite F' = m(v0)²/R

Since F = F0 = F'

GMm/R² = m(v0)²/R

GM = (v0)²R (1)

Also, he gravitational force on the satellite with speed vT at distance 3R is F1 = GMm/(3R)² = GMm/27R². This is also equal to the centripetal force on the satellite at 3R is F" = m(vT)²/3R

Since F1 = F'

GMm/27R² = m(vT)²/3R

GM = 27(vT)²R/3

GM = 9(vT)²R (2)

Equating (1) and (2),

(v0)²R = 9(vT)²R

dividing through by R, we have

9(vT)² = (v0)²

dividing through by 9, we have

(vT)² = (v0)²/9

taking square-root of both sides,

vT = v0/3

6 0

2 years ago

Mr. Rosa’s student has a backpack with a density of 30g/mL. How much mass does the backpack have if it takes up 12.3 cm cubed of

krek1111 [17]

Answer:

m = 369 grams

Explanation:

Given that,

The density of backpack, d = 30 g/mL

The volume of the backpack, V = 12.3 cm³

We need to find the mass of the backpack. The density of an object is given by :

$d=\dfrac{m}{V}\\\\m=d\times V\\\\m=30\times 12.3\\\\m=369\ g$

So, the mass of the backpack is 369 grams.

4 0

2 years ago