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Inessa [10]
3 years ago
5

Write each fraction as the sum of a whole number and a fraction less than 1

Mathematics
1 answer:
Tpy6a [65]3 years ago
7 0

Given:

The fractions are:

\dfrac{6}{5},\dfrac{11}{7},\dfrac{21}{4}

To find:

The each fraction as the sum of a whole number and a fraction less than 1.

Solution:

The given fraction is \dfrac{6}{5}.

\dfrac{6}{5}=\dfrac{5+1}{5}

\dfrac{6}{5}=\dfrac{5}{5}+\dfrac{1}{5}

\dfrac{6}{5}=1+\dfrac{1}{5}

Therefore, the given fraction \dfrac{6}{5} can be written as 1+\dfrac{1}{5}.

The given fraction is \dfrac{11}{7}.

\dfrac{11}{7}=\dfrac{7+4}{7}

\dfrac{11}{7}=\dfrac{7}{7}+\dfrac{4}{7}

\dfrac{11}{7}=1+\dfrac{4}{7}

Therefore, the given fraction \dfrac{11}{7} can be written as 1+\dfrac{4}{7}.

The given fraction is \dfrac{21}{4}.

\dfrac{21}{4}=\dfrac{20+1}{4}

\dfrac{21}{4}=\dfrac{20}{4}+\dfrac{1}{4}

\dfrac{21}{4}=5+\dfrac{1}{4}

Therefore, the given fraction \dfrac{21}{4} can be written as 5+\dfrac{1}{4}.

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Sliva [168]

Answer:

The correct option is;

c.) y - 6 = -4(x - (-2))

Step-by-step explanation:

We note that the figure Randolph is creating is a rectangle, therefore, we have;

\overline{WX}\perp \overline{XY}, therefore, we have;

\overline{WX} = \dfrac{1}{4} x + 4

∴ Slope \overline{WX} = 1/4

\overline{XY} must pas through the point (-2, 6)

Given that \overline{WX}\perp \overline{XY}, we have;

Slope \ \overline{XY} = \dfrac{-1}{Slope \ \overline{WX}}

\dfrac{y - 6}{x - (-2)} = -1/\dfrac{1}{4}  = -4

y - 6 = -4(x - (-2))

Therefore, the correct option is c.) y - 6 = -4(x - (-2)).

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Answer:

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Step-by-step explanation:

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Final answer: 125b^4
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Because the 2.5 is smaller than the 3, and the 5 is the greatest number out of those three numbers. :)
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