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olga_2 [115]
3 years ago
8

1.Explain why the reactivity of group 7 decreases as you move down the group. Try to use the sentence starters here: When group

7 elements react, their atoms….
As you move down the group, the outer shells get…

Therefore the force of attraction between the shells and the nucleus is….

This makes attracting an extra electron…​

Chemistry
1 answer:
blsea [12.9K]3 years ago
6 0

Answer:

Explanation:

When group 7 elements react , their atoms  gains  one  electron into their highest occupied  energy level ( outer shell) to form single negative - charged ion .

As you move down the group , the outer shells get increased  i.e an additional electron shell is added  thereby increasing the atomic radius  of the atom.  The electrons in the outer shell move further away from the nucleus as we go down the group .

Therefore the force of  attraction  between the shells and nucleus is decreased .

This makes attracting an extra electron difficult  . And so ability of the atom to attract electron to fill the outermost shell reduces which means the   reactiveness of the atom reduces.

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Which term names the container that holds the gear box and generator in a wind power system?.
spayn [35]

Answer:

Nacelle. The nacelle sits atop the tower and contains the gearbox, low- and high-speed shafts, generator, and brake.

Explanation:

5 0
2 years ago
How many atoms of fluoride are there in one molecule of nitrogen trifluoride?
Helga [31]

Answer:

there are three Fluorine atom. This is because Nitrogen give 3 electron away but fluorine can only take 1. So nitrogen gives 1 neutron to 3 fluorine each which makes it a stable compound

6 0
3 years ago
Read 2 more answers
What is the ph of a solution of 1.699 l of 1.25 m hcn, ka = 6.2 x 10-10, and 1.37 moles of nacn?
BlackZzzverrR [31]

The pH of a solution is 9.02.

c(HCN) = 1.25 M; concentration of the cyanide acid

n(NaCN) = 1.37 mol; amount of the salt

V = 1.699 l; volume of the solution

c(NaCN) = 1.37 mol ÷ 1.699 l

c(NaCN) = 0.806 M; concentration of the salt

Ka = 6.2 × 10⁻¹⁰; acid constant

pKa = -logKa

pKa = - log (6.2 × 10⁻¹⁰)

pKa = 9.21

Henderson–Hasselbalch equation for the buffer solution:

pH = pKa + log(cs/ck)

pH = pKa + log(cs/ck)

pH = 9.21 + log (0.806M/1.25M)

pH = 9.21 - 0.19

pH = 9.02; potential of hydrogen

More about buffer: brainly.com/question/4177791

#SPJ4

8 0
1 year ago
What is the percentage of lithium in lithium carbonate (Li2CO3)?
ale4655 [162]
Molar mass Li2CO3 = 73.89 g/mol
Molar mass Li = 6.94g/mol Li = 6.94*2 = 13.88g


% LI = 13.88/73.89*100 = 18.78% perfectly correct.
6 0
3 years ago
Read 2 more answers
Using the standard reduction potentials, Pb 2+(aq) + 2e– => Pb(s), E° = –0.13 V Fe 2+(aq) + 2e– => Fe(s), E° = –0.44 V Zn
mojhsa [17]

Answer:

Pb(s), Fe(s) and Zn(s) will reduce Mn^{3+} to Mn^{2+}

Fe(s) and Zn(s) will reduce Cr^{3+} to Cr

Explanation:

Standard reduction potential denotes ability to consume electrons from another species.

Hence, higher the standard reduction potential, higher will be the ability to oxidize another species.

Metal with E_{red}^{0} value lower than 1.51 V will donate electron to Mn^{3+} and thus reduces Mn^{3+} to Mn^{2+}.

So, Pb(s), Fe(s) and Zn(s) will reduce Mn^{3+} to Mn^{2+}.

Metal with E_{red}^{0} value lower than -0.40 V will donate electron to Cr^{3+} and thus reduces Cr^{3+} to Cr.

So, Fe(s) and Zn(s) will reduce Cr^{3+} to Cr.

6 0
3 years ago
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