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Georgia [21]
3 years ago
5

Chemical equation for sodium bromide​

Chemistry
1 answer:
Dafna1 [17]3 years ago
6 0
NaBr is the answer to what’s the chemical equation for sodium bromide
You might be interested in
If it takes 87.0 min for the concentration of a reactant to drop to 20.0% of its initial value in a first-order reaction, what i
charle [14.2K]

Answer:

0.0185 min⁻¹

Explanation:

Using integrated rate law for first order kinetics as:

[A_t]=[A_0]e^{-kt}

Where,  

[A_t] is the concentration at time t

[A_0] is the initial concentration

Given:

20.0 % of the initial values is left which means that 0.20 of [A_0] is left. So,

\frac {[A_t]}{[A_0]} = 0.20

t = 87.0 min

\frac {[A_t]}{[A_0]}=e^{-k\times t}

0.20=e^{-k\times 87.0}

<u>k = 0.0185 min⁻¹</u>

4 0
4 years ago
What is the boiling point of a solution made by adding 6.69 g of magnesium chloride to 250.0 g of water?. Use the formula of the
olya-2409 [2.1K]

Answer:

100.432ºC

Explanation:

Ebullioscopy is the elevation of the boiling point of a solvent that has a solute nonvolatile dissolved. The change in the temperature may be calculated by Raoult's law:

ΔT = Kb.W.i

Where <em>ΔT</em> is the temperature change, <em>Kb</em> is the ebullioscopy constant,<em> W</em> is the molality and <em>i</em> is the Van't Hoff factor, which determinates the particles that affect the proper.

The molality is:

W = m1/(M1xm2)

Where <em>m1</em> is the solute mass (in g), <em>M1</em> is the molar mass of the solute, and <em>m2</em> is the mass of the solvent (in kg).

The Van't Hoff factor is the number of final particles divided by the number of initial particles. Magnesium is from froup 2, so it forms the cation Mg⁺², and chlorine ins from group 7 and forms the anion Cl⁻, the salt is MgCl₂ and dissociates:

MgCl₂  → Mg⁺²(aq) + 2Cl⁻(aq)

So, it has 1 particle in initial, and 3 in final (1  Mg⁺² and 2 Cl⁻). So:

i = 3/1 = 3.

The molar mass of MgCl₂ is: 24.3 + 2x35.5 = 95.3 g/mol, m1 = 6.69g, m2 = 0.250 kg, so:

W = 6.69/(95.3x0.250)

W = 0.281 m

Then:

ΔT = 0.512x0.281x3

ΔT = 0.432ºC

The normal boling point of water is 100ºC, so

T - 100 = 0.432

T = 100.432ºC

6 0
3 years ago
How many moles of carbonate are there in sodium carbonate​
vaieri [72.5K]

There are 0.566 moles of carbonate in sodium carbonate.

<h3>CALCULATE MOLES:</h3>
  • The number of moles of carbonate (CO3) in sodium carbonate (Na2CO3) can be calculated by dividing the mass of carbonate in the compound by the molar mass of the compound.

  • no. of moles of CO3 = mass of CO3 ÷ molar mass of Na2CO3

  • Molar mass of Na2CO3 = 23(2) + 12 + 16(3)

  • = 46 + 12 + 48 = 106g/mol

  • mass of CO3 = 12 + 48 = 60g

  • no. of moles of CO3 = 60/106

  • no. of moles of CO3 = 0.566mol

  • Therefore, there are 0.566 moles of carbonate in sodium carbonate.

Learn more about number of moles at: brainly.com/question/1542846

5 0
3 years ago
Read 2 more answers
On x
Lena [83]

Answer:

2

Explanation:

1+1=2

6 0
3 years ago
Question 30
cestrela7 [59]

well #1 is A

and #2 is E  

well i did just do this


4 0
3 years ago
Read 2 more answers
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