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Georgia [21]
3 years ago
5

Chemical equation for sodium bromide​

Chemistry
1 answer:
Dafna1 [17]3 years ago
6 0
NaBr is the answer to what’s the chemical equation for sodium bromide
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HELP ASAP !!!!!
Anna35 [415]

Answer:

Explanation:

Take a random sample of nuts from the jar.  Let's take two handfuls, after shaking the jar and mixing the nuts thoroughly.  Separate the nuts into almonds and cashews.  Count each pile, then do the following calculation (these numbers are random, for example only).

                <u> Count</u>   <u>Percentage %</u>

Almonds       38        (38)/(87)x100

Cashews      <u> 49</u>         49/87x100

                      87          87/87 = 100%

Ratio of Almonds to Cashews:  <u>38/49</u>

3 0
3 years ago
How did Moseley establish a more accurate periodic table?
GrogVix [38]
<span>B.by arranging the elements according to atomic number instead of atomic mass</span> awnser is B
4 0
3 years ago
Read 2 more answers
What is the mass of calcium in 2.3•10^23 molecules of calcium phosphate
Katena32 [7]

Explanation:

N(Ca)=3×N(Ca₃(PO₄)₂)=

=3×2.3×10²³=6.9×10²³

6.02×10²³→40g

6.9×10²³→Xg

m(Ca)=X≈45.85g

3 0
3 years ago
Calculate the quantity of energy required to change 8.22 mol of liquid water to steam at 100oc. the molar heat of vaporization o
Ainat [17]
Since  the water  is  at  100 degrees  then   it take  40.6 kj/mol   to  change 1  mole of  water at 100 degrees into  steam at  100  degrees
  the  moles  of water  8.22mol
since  one  mole  take 40.6kj/mol   8.22mol  will  be  =
8.22mol  x  40.6 kj/mol =333.732  kj
 
4 0
3 years ago
Naturally occurring indium has two isotopes, indium-113(112.9040580 amu) and Indium-115 (114.9038780 amu. The atomic mass of ind
Kruka [31]

Answer:

The answer to your question is: letter c (96%)

Explanation:

Indium -113 (112-9040580 amu) ₁₁₃In

Indium-115 (114.9038780 amu)  ₁₁₅In

Atomic mass of Indium is 114.82 amu ₁₁₄.₈₂In

Formula

Atomic mass = m₁(%₁) +m₂(%₂)  / 100

%₁ = x I established this is an equation

%₂ = 100 - x

Substituting values

114.82 = 112.8040x + 114.9039(100-x) /100    and know we expand and simplify

114.82 = 112.8040x + 11490.39 - 114.9039x  /100

11482 = 112.8040x -114.9039x +11490.39

11482 - 11490.39 = 112.8040x -114.9039x

-8.39 = -2.099x

x = 3.99

Then % of Indium-115 = 100 - 3.99 = 96

5 0
4 years ago
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