Question

Please i have 15 minutes​

Answer 1

Answer:

$x = \dfrac{-\log 7}{\log 7 - \log 2}$

Step-by-step explanation:

$2^x = 7^{x + 1}$

Take the log of both sides.

$\log 2^x = \log 7^{x + 1}$

Use properties of log.

$x \log 2 = (x + 1) \log 7$

$x \log 2 = x \log 7 + \log 7$

$x \log 2 - x \log 7 = \log 7$

$x(\log 2 - \log 7) = \log 7$

$x = \dfrac{\log 7}{\log 2 - \log 7}$

$x = \dfrac{\log 7}{-(\log 7 - \log 2)}$

$x = \dfrac{-\log 7}{\log 7 - \log 2}$