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3 years ago

Sulfuric acid, H2SO4, can be neutralized by sodium hydroxide, NaOH. The unbalanced equation is:

Chemistry

1 answer:

kap26 [50]3 years ago

8 0

Answer:

Sulfuric acid, H2SO4, can be neutralized by sodium hydroxide, NaOH.

Explanation:

The balanced chemical equation of the reaction is:

$H_2SO_4(aq)+2NaOH(aq)->Na_2SO_4(aq)+2H_2O(l)$

A student who was asked to balance the reaction wrote the following:

H2SO4(aq) + Na2OH(aq) →Na2SO4(aq) + H3O(l)

This is wrong equation.

Because, the formula of sodium hydroxide is NaOH only and it is not $Na_2OH$ .

Because the valency of sodium will not exceed one and hydroxide ion has valency is also one.

H2SO4(aq) + Na2OH(aq) →Na2SO4(aq) + H3O(l)

for this equation, the left side mass of reactants is:

161.0g

Right side mass of products is:

161.0 g

But H3O(l) will not exist and $H_3O^+(aq)$ will exist.

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4 years ago

What is the molarity of a solution that contains 224 grams of KOH in 2<br> liters of solution?

adelina 88 [10]

Answer:

$\boxed {\boxed {\sf 2 \ M \ KOH}}$

Explanation:

Molarity is a measure of concentration in moles per liter.

<h3>1. Grams to Moles </h3>

The first step is to convert the amount of grams given to moles. The molar mass is used. This found on the Periodic Table and it's the same value as the atomic mass, but the units are grams per mole.

We have 224 grams of KOH. Look up the molar masses for the individual elements.

Potassium (K): 39.098 g/mol
Oxygen (O): 15.999 g/mol
Hydrogen (H): 1.008 g/mol

Since the compound's formula has no subscripts, 1 formula unit has 1 atom of each element. We can simply add the molar masses together to find KOH's molar mass.

KOH: 39.098 + 15.999 + 1.008=56.105 g/mol

Use this number as a ratio.

$\frac {56.105 \ g\ KOH}{1 \ mol \ KOH}$

Multiply by the value we are converting: 224 g KOH

$224 \ g \ KOH *\frac {56.105 \ g\ KOH}{1 \ mol \ KOH}$

Flip the ratio so the units of grams KOH cancel.

$224 \ g \ KOH *\frac {1 \ mol \ KOH}{56.105 \ g\ KOH}$

$224 *\frac {1 \ mol \ KOH}{56.105}$

$\frac {224}{56.105} \ mol \ KOH$

$3.992514036 \ mol \ KOH$

<h3>2. Calculate Molarity </h3>

Remember molarity is moles per liter.

$molarity = \frac{moles}{liters}$

We just calculated the moles and we know there are 2 liters of solution.

$molarity = \frac{ 3.992514036 \ mol \ KOH}{ 2 \ L}$

$molarity= 1.996257018 \ mol \ KOH/ L$

<h3>3. Round and Convert Units </h3>

First, let's round. The original values have 3 and 1 significant figures. We go with the lowest number: 1. For the number we found, that is the ones place.