Alright here the answer to number 2
When the initial speed given is 7.5m/s at an angle of 27° , ball will go
4.637 meters.
Assume no air opposition to the ball ;
Vertical component of ball is sin 27° = 0.453
0.453* 7.5 = 3.404 meters /sec
Time taken to reach ground is :
3.404 = -3.404+9.8*t
t= 6.808/9.8= 0.694 sec
Horizontal component is 7.5*cos27°= 6.682m/s
Distance = speed * time
=6.682 * 0.694
=4.637 meters
Horizontal distance it can cover in 0.694 sec is 4.637 meters
So range of ball is 4.637 meters.
Form of motion experienced by an object or particle that is projected near surface of the earth and moves along a curve is called Projectile motion. Three types of projectile motion are Horizontal projectile motion. Oblique projectile motion and Projectile motion on an inclined plane.
To know more about projectile motion, refer
brainly.com/question/24216590
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I'm guessing that you mean like this:
-- The ruler is held with zero at the bottom, and the centimeter markings
increase as you go up the ruler.
-- You place your fingers with the ruler and the zero mark between them.
-- The number where you catch the ruler is the distance it has fallen.
Then, all we have to find is the time it takes for the ruler to fall 11.3 cm .
Here's the formula for the distance an object falls from rest
in a certain time:
Distance = (1/2) (gravity) (time)²
On Earth, the acceleration of gravity is 9.8 m/s².
So we can write ...
11.2 cm = (1/2) (9.8 m/s²) (time)²
or
0.112 meter = (4.9 m/s²) (time)²
Divide each side
by 4.9 m/s² : (0.112 m) / (4.9 m/s²) = time²
(0.112 / 4.9) sec² = time²
Square root
each side: time = √(0.112/4.9 sec²)
= √ 0.5488 sec²
= 0.74 second (rounded)