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3 years ago

12

• The average length is cm. This is the mean or average. b)• Subtract the highest value from the lowest value:

_ cm. This is the range or spread. c)• Divide this number by 2: _______ cm. This is the approximate ± range from the average. d)• The precision of the measurement can be shown as an average ± range. The precision of the measurement was ________±_____ cm.

1 answer:

coldgirl [10]3 years ago

7 0

16, 5 , 3 = 16+5+3= 24 + 3

So at the end put 24 + 3 cm
And put 16 for the lengths
For the value 5 and for the diving thingy 3

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If the average speed of a person was 1.2 meters/second, does this mean that their speed was exactly 1.2 meters/second the whole

alexandr1967 [171]

Average speed is defined by the following formula

$v = \frac{D}{t}$

here

D = total distance that an object move from its initial position to final position

t = total time of the motion

so here we will say that there is no such relation between initial or final speed or we can say maximum or minimum speed of object with average speed of object.

We only need to find the total distance and total time of motion in order to find the average speed

here we can see many examples like let say an object moves with speed v1 for time t1 and then with speed v2 for time t2 then here average speed is given as

$d = v_1 t_1 + v_2t_2$

since we know that distance covered is product of speed and time

that's why we used above equation for finding total distance

now the average speed will be

$v_{avg} = \frac{v_1t_1 + v_2 t_2}{t_1 + t_2}$

so this is how we can find the average speed for above motion

so average speed is always between maximum and minimum speed any value in-between.

It is neither the maximum value nor it is minimum value

7 0

3 years ago

A horizontal 745 N merry-go-round of radius

Arturiano [62]

Answer:

The kinetic energy of the merry-goround after 3.62 s is 544J

Explanation:

Given :

Weight w = 745 N

Radius r = 1.45 m

Force = 56.3 N

To Find:

The kinetic energy of the merry-go round after 3.62 = ?

Solution:

Step 1: Finding the Mass of merry-go-round

$m = \frac{ weight}{g}$

$m = \frac{745}{9.81 }$

m = 76.02 kg

Step 2: Finding the Moment of Inertia of solid cylinder

Moment of Inertia of solid cylinder I = $0.5 \times m \times r^2$

Substituting the values

Moment of Inertia of solid cylinder I

=> $0.5 \times 76.02 \times (1.45)^2$

=> $0.5 \times 76.02\times 2.1025$

=> $79.91 kg.m^2$

Step 3: Finding the Torque applied T

Torque applied T = $F \times r$

Substituting the values

T = $56.3 \times 1.45$

T = 81.635 N.m

Step 4: Finding the Angular acceleration

Angular acceleration , $\alpha = \frac{Torque}{Inertia}$

Substituting the values,

$\alpha = \frac{81.635}{79.91}$

$\alpha = 1.021 rad/s^2$

Step 4: Finding the Final angular velocity

Final angular velocity , $\omega = \alpha \times t$

Substituting the values,

$\omega = 1.021 \times 3.62$

$\omega = 3.69 rad/s$

Now KE (100% rotational) after 3.62s is:

KE = $0.5 \times I \times \omega^2$

KE = $0.5 \times 79.91 \times 3.69^2$

KE = 544J

6 0

4 years ago

Convert the following measurements. Only type numbers and decimals into the answer boxes:

ivolga24 [154]

Answer:

2m 4m2Explanation:rteji3ujnrej

6 0

3 years ago

Read 2 more answers

A thin block of soft wood with a mass of 0.072 kg rests on a horizontal frictionless surface. A bullet with a mass of 4.67 g is

kozerog [31]

Answer:

v’= 279.66 m / s

Explanation:

We work this exercise using the conservation of the moment. For this we define the system formed by the two blocks, therefore the forces during the collision are internal of the action and reaction type.

Initial instant. Before the crash

p₀ = m v₀ + 0

Final moment. After the crash

p_f = m v + M v ’

how the tidal wave is preserved

p₀ = p_f

m v₀ = m v + M v ’

v = $\frac{m v_o - Mv'}{m}$

let's calculate

v ’= $\frac{0.00467 \ 619 - 0.072 \ 22}{0.004676}$

v ’= $\frac{2.89- 1.584}{ 0.00467}$

v ’= 279.66 m / s

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3 years ago

A number of compounds containing the heavier noble gases, and especially xenon, have been prepared. One of these is xenon hexafl

aalyn [17]

Answer:

The answer is "82.2 torr"

Explanation:

moles of Xe:

$= \frac{0.06}{131.293} \\\\ =0.00045699313 \ \mol$

moles of $F_2$ :

$= \frac{0.0274}{38} \\\\= 0.00072105263\ \ mol$

moles of produced $XeF_2:$

$= 0.00024$

moles of left $Xe$ :

$= 0.00021$

Calculate the Pressure:

$= \frac{(0.08206\times 0.00024 \times 293)}{(.1)} + \frac{(0.08206\times 0.00021 \times 293)}{(.1)} \\\\= 0.10819611 \ \ atm \\\\ = 0.10819611 \times 760 \\\\ = 82.2 \ \ torr$

5 0

3 years ago