Answer:
4.36 seconds
Explanation:
According to the question;
- Force is 550 N
- Mass of the car is 1200 kg
- Velocity of the car is 2.0 m/s
We are needed to find the time the car must the tow track pull the car.
- From Newton's second law of motion;
- Impulsive force, F = Mv÷t , where m is the mass, v is the velocity and t is the time.
Rearranging the formula;
t = mv ÷ F
Thus;
Time = (1200 kg × 2.0 m/s²) ÷ 550 N
= 4.36 seconds
Thus, the time needed to pull the car is 4.36 seconds
Explanation:
Fluid gauge pressure is:
P = ρgh
where ρ is the fluid density and h is the depth of the fluid.
P = (1000 kg/m³) (9.8 m/s²) (1642 m)
P = 16,091,600 Pa
Rounded to four significant figures, the gauge pressure is 16.09 MPa.
Answer:
angular velocity(ω) is the rate change of angular displacement.
ω=θ/t and it SI unit is rad/s
Explanation:
this is very similar with the definition of linear velocity (rate of change of displacement). it specifies the angular speed of an object and the axis about which the object is rotating.
Answer:
time required after impact for a puck is 2.18 seconds
Explanation:
given data
mass = 30 g = 0.03 kg
diameter = 100 mm = 0.1 m
thick = 0.1 mm = 1 ×
m
dynamic viscosity = 1.75 ×
Ns/m²
air temperature = 15°C
to find out
time required after impact for a puck to lose 10%
solution
we know velocity varies here 0 to v
we consider here initial velocity = v
so final velocity = 0.9v
so change in velocity is du = v
and clearance dy = h
and shear stress acting on surface is here express as
= µ 
so
= µ
............1
put here value
= 1.75×
× 
= 0.175 v
and
area between air and puck is given by
Area =
area =
area = 7.85 ×
m²
so
force on puck is express as
Force = × area
force = 0.175 v × 7.85 × 
force = 1.374 ×
v
and now apply newton second law
force = mass × acceleration
- force = 
- 1.374 ×
v = 
t = 
time = 2.18
so time required after impact for a puck is 2.18 seconds
In Linear motion the swimmer swims