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nikitadnepr [17]
3 years ago
8

A 52–newton bird feeder is tied to a cord, which is attached to a tree branch. Describe the tension force of the rope.

Physics
2 answers:
Sloan [31]3 years ago
7 0

Answer:

option C. for plato users

a 52–newton tension force pulls down on the branch, and a 52–newton tension force pulls up on the bird feeder.

Explanation:

got 100 on the test :)

iris [78.8K]3 years ago
4 0
If you are given a 52 Newton bird feeder tied to a cord, it means that it has a weight of 52 Newton. Since the bird feeder is not moving, we assume it to exert a force downward, that is its weight, and the cord that ties it, the force is upward. This upward force is the tension and is therefore equal to 52N.
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A ball has mass of 140g. what is the force to accelerate the ball at 25m/s
Fittoniya [83]

We know, F = m * a

Here, m = 140 g = 0.140 Kg

a = 25 m/s2

It would be: F = 0.140 * 25 = 3.5 N

So your answer would be 3.5N


6 0
3 years ago
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Compressed gases aren't ideal. Let's consider a gas that's non-ideal only because the volume available to each of the N molecule
Colt1911 [192]

Answer:

8563732.58906 Pa

3992793.23326 Pa

5708.00923 J

Explanation:

V = Volume

N = Number of molecules = 3\times 6.023\times 10^{23}

T = Temperature = 300 K

b = 7\times 10^{-29}\ m^3

k_ = Boltzmann constant = 1.38\times 10^{-23}\ J/K

P = Pressure

We have the equation

P(V-Nb)=NkT\\\Rightarrow P=\dfrac{NkT}{V-Nb}\\\Rightarrow P=\dfrac{3\times 6.023\times 10^{23}\times 1.38\times 10^{-23}\times 300}{0.001-3\times 6.023\times 10^{23}\times 7\times 10^{-29}}\\\Rightarrow P=8563732.58906\ Pa

The pressure is 8563732.58906 Pa

For isothermal expansion

P_1(V_1-Nb)=P_2(V_2-Nb)\\\Rightarrow P_2=\dfrac{P_1(V_1-Nb)}{V_2-Nb}\\\Rightarrow P_2=\dfrac{8563732.58906(0.001-3\times 6.023\times 10^{23}\times 7\times 10^{-29})}{0.002-3\times 6.023\times 10^{23}\times 7\times 10^{-29}}\\\Rightarrow P_2=3992793.23326\ Pa

The pressure is 3992793.23326 Pa

Work done is given by

dw=Pdv\\\Rightarrow W=\int_{v_1}^{v_2}\dfrac{NkT}{V-Nb}dv\\\Rightarrow W=NkTln\dfrac{V_2-Nb}{V_1-Nb}\\\Rightarrow W=3\times 6.023\times 10^{23}\times 1.38\times 10^{-23}\times 300ln\dfrac{0.002-3\times 6.023\times 10^{23}\times 7\times 10^{-29}}{0.001-3\times 6.023\times 10^{23}\times 7\times 10^{-29}}\\\Rightarrow W=5708.00923\ J

The work done is 5708.00923 J

7 0
3 years ago
Standing on the roof of a (42.0+A) m tall building, you throw a ball straight up with an initial speed of (14.5+B) m/s. If the b
RSB [31]
First, we must find the vertical distance traveled upwards by the ball due to the throw. For this, we will use the formula:

2as = v² - u²

Because the final velocity v is 0 in such cases

s = -u²/2a; because both u and a are downwards, the negative sign cancels

s = 14.5² / 2*9.81
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Next, to find the time taken to reach the ground, we need the height above the ground. This is:
45 + 10.72 = 55.72 m

We will use the formula 
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4 0
3 years ago
Which of the following objects have gravitational potential energy?
Brut [27]

Answer:

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Explanation:

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3 years ago
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An oven uses 4500 watts of power in 2 minutes, how much work was done?
jolli1 [7]
First of all we state the formula
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we can rearrange this formula as well
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work done = 4500 x 120
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4 0
2 years ago
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