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andrezito [222]
3 years ago
7

Help to find the answer!

Mathematics
2 answers:
stepan [7]3 years ago
6 0

Answer:

  • 30 units

Step-by-step explanation:

<u>The ratio of sides in 45º-45º-90º triangle is:</u>

  • a : b : c = 1 : 1 : √2

<u>If both a and b are 15√2, the hypotenuse is:</u>

  • c = 15√2*√2 = 15*2 = 30
alexira [117]3 years ago
6 0

Let's consider the given triangle be ∆ABC. First of all we must know the unique property of triangle 45° - 45° - 90°. In this the ratio of sides of the triangle is given by,

\implies a : b : c = 1 : 1 : √2

Now as per your question elaborating it by placing values of sides in our ∆ABC,

Where,

  • c = hypotenuse
  • a & b = two sides

:\implies\sf{c = 15 \sqrt{2}  \times  \sqrt{2} }

:\implies\sf{c = 15 \times  \sqrt{2}  \times  \sqrt{2} }

:\implies\sf{c = 15 \times 2}

:\implies\sf{c = 30}

  • The length of hypotenuse is <u>3</u><u>0</u><u>c</u><u>m</u><u>.</u>

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scoray [572]

Answer: \frac{1}{8}\ lb

Step-by-step explanation:

According to the information given in the exercise, you know that the total amount of butter (in pounds) that were divided evenly, is:

total=\frac{3}{4}\ lb

The exercise explains that they filled six dishes with that division. Therefore, in order to calculate the value of the variable "x", you need to divide \frac{3}{4}\ lb by 6.

But first it is important to remember the Division of fractions:

\frac{a}{b}\div\frac{c}{d}=\frac{a}{b}\div\frac{d}{c}=\frac{ad}{bc}

Therefore, applying that rule, you get:

\frac{3}{4}\ lb\div6=(\frac{3}{4}\ lb)(\frac{1}{6})=\frac{3}{24}\ lb

Finally, reducing the fraction you get the following result expressed as a fraction:

=\frac{1}{8}\ lb

6 0
4 years ago
A local school donated canned goods to help the community. Cans were packed into boxes each weighing 16.4 pounds. The volunteers
Alex777 [14]
B if not comment so yeah ok
7 0
3 years ago
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Can someone explain this to me.
almond37 [142]

Answer:

option D

3*(\sqrt{x}+\sqrt{x-3})

Step-by-step explanation:

Given in the question an expression,

\frac{9}{\sqrt{x} -\sqrt{x-3}}

Step 1

Divide and multiple by \sqrt{x}+\sqrt{x-3} to remove radical sign from denominator.

\frac{9}{\sqrt{x} -\sqrt{x-3}}*\frac{\sqrt{x} +\sqrt{x-3}}{\sqrt{x} +\sqrt{x-3}}

Step 2

Apply a² - b² = (a+b)(a-b)

\frac{9*\sqrt{x}+\sqrt{x-3}}{\sqrt{x^{2}}-\sqrt{(x-3)^{2}}}}

Step 3

\frac{9*\sqrt{x}+\sqrt{x-3}}{x-x+3}

Step 4

\frac{9*\sqrt{x}+\sqrt{x-3}}{3}

Step 5

3*(\sqrt{x}+\sqrt{x-3})

7 0
3 years ago
3x + 2z - 4y - 6 + 4z + 7y
Anon25 [30]

Answer:

3x(2z+4z)+(−4y+7y)−6

Step-by-step explanation:

1 Collect like terms.

3x+(2z+4z)+(−4y+7y)−6

2 Simplify.

3x+(2z+4z)+(−4y+7y)−6

3x+6z+3y−6

5 0
3 years ago
What is the largest power of 2 that is a divisor of 13^4 - 11^4?
OverLord2011 [107]

Answer:

2^5

Step-by-step explanation:

Given:

(13^4 - 11^4)(13^2+11^2)

add all together with exponents

=48*290

= Then turn into a smaller exponent

= 2^4 * 3 * 2*145

combine like terms

2^4 *2

=2^5

5 0
2 years ago
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