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andrezito [222]
3 years ago
7

Help to find the answer!

Mathematics
2 answers:
stepan [7]3 years ago
6 0

Answer:

  • 30 units

Step-by-step explanation:

<u>The ratio of sides in 45º-45º-90º triangle is:</u>

  • a : b : c = 1 : 1 : √2

<u>If both a and b are 15√2, the hypotenuse is:</u>

  • c = 15√2*√2 = 15*2 = 30
alexira [117]3 years ago
6 0

Let's consider the given triangle be ∆ABC. First of all we must know the unique property of triangle 45° - 45° - 90°. In this the ratio of sides of the triangle is given by,

\implies a : b : c = 1 : 1 : √2

Now as per your question elaborating it by placing values of sides in our ∆ABC,

Where,

  • c = hypotenuse
  • a & b = two sides

:\implies\sf{c = 15 \sqrt{2}  \times  \sqrt{2} }

:\implies\sf{c = 15 \times  \sqrt{2}  \times  \sqrt{2} }

:\implies\sf{c = 15 \times 2}

:\implies\sf{c = 30}

  • The length of hypotenuse is <u>3</u><u>0</u><u>c</u><u>m</u><u>.</u>

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Alecsey [184]

Answer:

C. 15 cm

Explanation:

The radius is the same in a circle. PA and PB has same length of 8 cm.

In order to find AC, find the length of PA and PC.

Here given:

  • PA = 8 cm
  • PC = PB + BC = 8 cm + 9 cm = 17 cm

Hence solve using Pythagoras theorem:

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  • AC² + 8² = 17²
  • AC² = 289 - 64
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2 years ago
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IgorLugansk [536]

Answer:

4

Step-by-step explanation:

Lets start by plugging in our (a) value

a^2 + 5a + 4

(-5)^2 + 5(-5) +4

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4 is your final answer!

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jek_recluse [69]

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17

Step-by-step explanation:

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Scores for a common standardized college aptitude test are normally distributed with a mean of 493 and a standard deviation of 9
Tomtit [17]

Answer:

34.01% probability that his score is at least 532.1.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 493, \sigma = 95

If 1 of the men is randomly selected, find the probability that his score is at least 532.1.

This is 1 subtracted by the pvalue of Z when X = 532.1. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{532.1 - 493}{95}

Z = 0.41

Z = 0.41 has a pvalue of 0.6591

1 - 0.6591 = 0.3409

34.01% probability that his score is at least 532.1.

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