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2 years ago

Yooo my ban is up!!!! 5+37=4-3x

2 answers:

7 0

Answer:

5+37=4-3x

We move all terms to the left:

5+37-(4-3x)=0

We add all the numbers together, and all the variables

-(-3x+4)+5+37=0

We add all the numbers together, and all the variables

(hope that helps you out)

-(-3x+4)+42=0

We get rid of parentheses

3x-4+42=0

We add all the numbers together, and all the variables

3x+38=0

We move all terms containing x to the left, all other terms to the right

3x=-38

x=-38/3

x=-12+2/3

(just in case you didn’t want it in the comments)

Serga [27]2 years ago

7 0

Answer:

x = -38/3

Step-by-step explanation:

lol

Simplify 5 + 37 = 42

42 = 4 - 3x

Subtract 4 from both sides

42 - 4 = -3x

Simplify 42 - 4 = 38

38 = -3x

-38/3 = x

MAY I PLEASE HAVE BRAINLIEST!!???

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A car is driving northwest at vv mph across a sloping plain whose height, in feet above sea level, at a point nn miles north and

solong [7]

Northwest is 45 degrees north of west. If a car travels a distance x miles northwest, its northerly component gains x/sqrt(2) miles and its easterly component LOSES xsqrt(2)/ miles.

Resultant height is h = 4500 + 100x/sqrt(2) - 75x/sqrt(2) = [25/sqrt(2)]x + 4500
dh/dt = [25/sqrt(2)]dx/dt = [25/sqrt(2)]v

7 0

2 years ago

Please help me with these, oh sweet jesus

Lelechka [254]

Answer:

77. $\cot^{6} x = \cot^{4} x \csc^{2}x - \cot^{4} x$ Proved

78. $\sec^{4}x \tan^{2} x = \sec^{2}x [\tan^{2}x + \tan^{4}x ]$ Proved

79. $\cos^{3} x\sin^{2} x = [\sin^{2}x - \sin^{4}x] \cos x$ Proved.

80. $\sin^{4}x - \cos^{4}x = 1 - 2\cos^{2}x + 2 \cos^{4} x$ Proved.

Step-by-step explanation:

77. Left hand side

= $\cot^{6} x$

= $\cot^{4} x \times \cot^{2} x$

= $\cot^{4}x [\csc^{2}x - 1]$

{Since we know, $\csc^{2} x - \cot^{2}x = 1$ }

= $\cot^{4} x \csc^{2}x - \cot^{4} x$

= Right hand side (Proved)

78. Left hand side

= $\sec^{4}x \tan^{2} x$

= $\sec^{2} x [1 + \tan^{2}x] \tan^{2} x$

{Since $\sec^{2}x - \tan^{2}x = 1$ }

= $\sec^{2}x [\tan^{2}x + \tan^{4}x ]$

= Right hand side (Proved)

79. Left hand side

= $\cos^{3} x\sin^{2} x$

= $\cos x[1 - \sin^{2} x] \sin^{2} x$

{Since $\sin^{2}x + \cos^{2} x = 1$ }

= $[\sin^{2}x - \sin^{4}x] \cos x$

= Right hand side

80. Left hand side

= $\sin^{4}x - \cos^{4}x$

= $[\sin^{2}x + \cos^{2}x]^{2} - 2\sin^{2} x \cos^{2}x$

{Since $\sin^{2}x + \cos^{2} x = 1$ }

= $1 - 2\cos^{2} x[1 - \cos^{2}x ]$

= $1 - 2\cos^{2}x + 2 \cos^{4} x$

= Right hand side. (Proved)

7 0

3 years ago

An item costs $45.60. If there is a 30% discount on the item, what is the discounted cost of the item?

kondor19780726 [428]

Discounted Cost= Cost of Item - (Cost of Item * % Discount)

= $45.60 - ($45.60 * 30%)
convert % to decimal (30% ÷ 100)

= 45.60 - (45.60 * 0.30)
multiply in parentheses

= 45.60 - 13.68

= $31.92 discounted cost

ANSWER: The discounted cost of the item is $31.92 (savings of $13.68).

Hope this helps! :)

6 0

3 years ago

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