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viva [34]
3 years ago
9

Use your answer in part (a) to find the two values of m for which (m-2)2 -4(m-2)+2=0​

Mathematics
1 answer:
Olegator [25]3 years ago
5 0

Answer:

Step-by-step explanation:

Replace m - 2 with x.  Then we have x^2 - 4x + 2 = 0.

Completing the square, we get x^2 - 4x + 4 - 4 + 2 = 0, or

x^2 - 4x + 4 - 2 = 0, or

(x - 2)^2 - 2 = 0, or (x - 2)^2 = 2

Solve for x:  Take the square root of both sides.  Then:

x - 2 = ±√2 and x = 2 + √2 and x = 2 - √2

But x = m - 2; therefore, x = m - 2 = 2 - √2.  Solving for m, we get

m = 4 - √2.    

Also:  m - 2 = 2 + √2 leads to m = 4 + √2.  

The given equation is true for these two values of m.        

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