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laila [671]
4 years ago
10

A 160-kg object and a 460-kg object are separated by 3.40 m.(a) Find the magnitude of the net gravitational force exerted by the

se objects on a 33.0-kg object placed midway between them.
Physics
1 answer:
ivann1987 [24]4 years ago
6 0

Answer:

The net gravitational force exerted by these objects is 5.712\times10^{-8}\ N

Explanation:

Given that,

Mass of another object m = 33.0 kg

Mass M₁ = 160 kg

Mass M₂ = 460 kg

Distance = 3.40 m

We need to calculate the net gravitational force

Using formula,

F=\dfrac{GM_{2}m}{r^2}-\dfrac{GM_{1}m}{r^2}

F=Gm(\dfrac{M_{2}-M_{1}}{r^2})

Where, G = gravitational constant

m = mass of another object

M_{1}= mass of first object

M_{2}= mass of second object

r = distance

Put the value into the formula

F=6.67\times10^{-11}\times33.0\times\dfrac{460-160}{(3.40)^2}

F=5.712\times10^{-8}\ N

Hence, The net gravitational force exerted by these objects is 5.712\times10^{-8}\ N

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75kg man climbs a mountain 1000m high in 3hrs and uses 4100 joulse/min. (a) calculate the power consumption in watt, (b) what is
mr Goodwill [35]

Answer:

Explanation:

a) Power consumption is 4100 J/min / 60 s/min = 68.3 W(atts)

work done raised the potential energy

b) 75(9.8)(1000) / (3(3600)) = 68.055555... 68.1 W

c) efficiency is 68.1 / 68.3 = 0.99593... or nearly 100%

Not a very likely scenario.

3 0
3 years ago
A train traveling at 25 m/s is blowing its whistle at 440 Hz as it crosses a level crossing. You are waiting at the crossing and
ohaa [14]

Answer:

b) 472HZ, 408HZ

Explanation:

To find the frequencies perceived when the bus approaches and the train departs, you use the Doppler's effect formula for both cases:

f_o=f\frac{v_s+v_o}{v_s-v}\\\\f_o=f'\frac{v_s-v_o}{v_s+v}\\\\

fo: frequency of the source = 440Hz

vs: speed of sound = 343m/s

vo: speed of the observer = 0m/s (at rest)

v: sped of the train

f: frequency perceived when the train leaves us.

f': frequency when the train is getTing closer.

Thus, by doing f and f' the subjects of the formulas and replacing the values of v, vo, vs and fo you obtain:

f=f_o\frac{v_s-v}{v_s+v_o}=(440Hz)\frac{340m/s-25m/s}{340m/s}=408Hz\\\\f'=f_o\frac{v_s+v}{v_s-v_o}=(440Hz)\frac{340m/s+25m/s}{340m/s}=472Hz

hence, the frequencies for before and after tha train has past are

b) 472HZ, 408HZ

6 0
3 years ago
if the efficiency of an electric furnace is 96%, then 96% of the input energy is transformed into thermal energy. what is the ot
Nonamiya [84]
It is wasted, most likely as light, in this case, or it is lost during the transport of electricity.
5 0
4 years ago
A 6.2 kg object moving in the +x direction at 5.3 m/s collides head-on with an 7.8 kg object moving in the −x direction at 2.5 m
Crank

Answer:

10ms kg 88.2

Explanation:

Toook test

8 0
4 years ago
The area of the piston to the master cylinder in a hydraulic braking system of a car is 0.6 square inches. If a force of 5.6 lb
balu736 [363]

Answer:

16.8 lb is the force on the brake pad of one wheel.

Explanation:

Force applied on the piston = F_1=5.6 lb

Area of the piston = A_1=0.6 inches^2

Force applied on the brakes = F_2

Area of the brakes = A_2=1.8 inches^2

Applying Pascal's law: 'For an incompressible fluid pressure at one surface is equal to the pressure at other surface'.

\frac{F_1}{A_2}=\frac{F_2}{A_2}

F_2=\frac{5.6 lb\times 1.8 inhes^2}{0.6 inches^2}=16.8 lb

16.8 lb is the force on the brake pad of one wheel.

5 0
4 years ago
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