Question

A 160-kg object and a 460-kg object are separated by 3.40 m.(a) Find the magnitude of the net gravitational force exerted by these objects on a 33.0-kg object placed midway between them.

Answer 1

Answer:

The net gravitational force exerted by these objects is $5.712\times10^{-8}\ N$

Explanation:

Given that,

Mass of another object m = 33.0 kg

Mass M₁ = 160 kg

Mass M₂ = 460 kg

Distance = 3.40 m

We need to calculate the net gravitational force

Using formula,

$F=\dfrac{GM_{2}m}{r^2}-\dfrac{GM_{1}m}{r^2}$

$F=Gm(\dfrac{M_{2}-M_{1}}{r^2})$

Where, G = gravitational constant

m = mass of another object

$M_{1}$= mass of first object

$M_{2}$= mass of second object

r = distance

Put the value into the formula

$F=6.67\times10^{-11}\times33.0\times\dfrac{460-160}{(3.40)^2}$

$F=5.712\times10^{-8}\ N$

Hence, The net gravitational force exerted by these objects is $5.712\times10^{-8}\ N$