Question

The temperature of a heat engine is 500 K. Some of the heat generated by the engine flows to the surroundings, which are

Answer 1

Answer:

The efficiency of the engine is 75%  under given conditions.

Explanation:

Efficiency is defined as the ratio of work done by the engine to the total heat supplied to a heat engine. We know work done by the heat engine be difference between total heat supplied $\left(Q_{h}\right)$ by total heat utilized $\left(Q_{c}\right)$. We can derive formula for efficiency by considering the above factors, $\text { efficiency }=\frac{\text { work done }}{\text { heat suplied }}=\frac{Q_{h}-Q_{c}}{Q_{h}}=1-\frac{Q_{c}}{Q_{h}}=1-\frac{T_{1}}{T_{2}} \therefore \text { efficiency }=1-\frac{T_{1}}{T_{2}}$  

Now consider a heat engine is at a temperature of 500K and the heat produced by the engine released to the surroundings at a temperature of 125K. The efficiency is calculated by using the above formula, $\text { efficiency }=1-\frac{T_{1}}{T_{2}}=1-\frac{125}{500}=1-0.25=0.75$

∴ Efficiency of the engine is 75%