Answer:
Part A. The half-cell B is the cathode and the half-cell A is the anode
Part B. 0.017V
Explanation:
Part A
The electrons must go from the anode to the cathode. At the anode oxidation takes place, and at the cathode a reduction, so the flow of electrons must go from the less concentrated solution to the most one (at oxidation the concentration intends to increase, and at the reduction, the concentration intends to decrease).
So, the half-cell B is the cathode and the half-cell A is the anode.
Part B
By the Nersnt equation:
E°cell = E° - (0.0592/n)*log[anode]/[cathode]
Where n is the number of electrons being changed in the reaction, in this case, n = 2 (Sn goes from S⁺²). Because the half-reactions are the same, the reduction potential of the anode is equal to the cathode, and E° = 0 V.
E°cell = 0 - (0.0592/2)*log(0.23/0.87)
E°cell = 0.017V
Noble gases react very unwillingly, because the outermost shell of electrons orbiting the nucleus is full, giving these gases no incentive to swap electrons with other elements. As a result, there are very few compounds made with noble gases. Like its noble gas comrades, neon is odorless and colorless.
Converting temperature of 68°F to °C gives 20 °C.
Converting temperature of 68°F to K gives 293 K.
<h3>What is temperature conversion?</h3>
Temperature conversion is the process of converting the measurement units of the temperature recorded in a particular unit to another unit.
The various units of Temperature include;
- degree Celsius
- degree Fahrenheit
- degree Kelvin
Temperature is measured with thermometer and it records the hotness or coldness of a body.
<h3>Converting 68°F to °C</h3>
F = 1.8C + 32
(F - 32/1.8) = C
(68 - 32) / 1.8 = C
20 ⁰C = 68 ⁰F
<h3>Converting 20°C to K</h3>
0 °C = 273 K
20 °C = 273 + 20 = 293 K
Learn more about temperature conversion here: brainly.com/question/23419049
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