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RideAnS [48]
3 years ago
14

Which is colder, 0°C or 20°F?

Physics
2 answers:
Allushta [10]3 years ago
8 0
20 degrees F because 0 degrees celcius is around 32 degrees F 
Mashutka [201]3 years ago
7 0

In order to compare the two temperatures, we need to convert 20°F into Celsius. The formula we need to use is:

T(^{\circ}C)=\frac{5}{9}(T(^{\circ}F)-32)

Substituting 20°F, we find

T(^{\circ}C)=\frac{5}{9}(20^{\circ}F-32) =-6.7^{\circ}C


And this is less than 0°C, so the answer is

20°F is colder than 0°C.


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Define quant......am physics​
Bas_tet [7]

Answer:

<h2><u>✍</u><u> </u><u>What is quantum physics?</u></h2>

  • ➳ It's the physics that explains how everything works; the best description we have of the nature of the particles that make up matter and the forces with which they interact.
  • Quantum physics underlies how atoms work, and so why chemistry and biology work as they do.
7 0
3 years ago
Read 2 more answers
the coefficient of kinetic friction between a couch and the floor is 0.65. if the couch has a mass of 42 kg and you push it with
Anna [14]

Explanation:

The net force along the horizontal direction is

\sum{F_x} = F_{applied} - f

where f is the frictional force. We can find the frictional force by looking at the vertical forces acting on the couch:

\sum{F_y} = N - mg = 0 \Rightarrow N = mg

From the definition of frictional force,

f = \mu{N} = \mu{mg} = (0.65)(42\:\text{kg})(9.8\:\text{m/s}^2)

\:\:\:\:= 267.5\:\text{N}

Therefore, the net force on the couch is

\sum{F_x} = 600\:\text{N} - 267.5\:\text{kN} = 332.5\:\text{N}

4 0
2 years ago
Given vectors D (3.00 m, 315 degrees wrt x-axis) and E (4.50 m, 53.0 degrees wrt x-axis), find the resultant R= D + E. (a) Write
Eva8 [605]

Answer:

  • R = ( 4.831 m , 1.469 m )
  • Magnitude of R = 5.049 m
  • Direction of R relative to the x axis= 16°54'33'

Explanation:

Knowing the magnitude and directions relative to the x axis, we can find the Cartesian representation of the vectors using the formula

\vec{A}= | \vec{A} | \ ( \ cos(\theta) \ , \ sin (\theta) \ )

where | \vec{A} | its the magnitude and θ.

So, for our vectors, we will have:

\vec{D}= 3.00 m \ ( \ cos(315) \ , \ sin (315) \ )

\vec{D}=  ( 2.121 m , -2.121 m )

and

\vec{E}= 4.50 m \ ( \ cos(53.0) \ , \ sin (53.0) \ )

\vec{E}= ( 2.71 m , 3.59 m )

Now, we can take the sum of the vectors

\vec{R} = \vec{D} + \vec{E}

\vec{R} = ( 2.121 \ m , -2.121 \ m ) + ( 2.71 \ m , 3.59 \ m )

\vec{R} = ( 2.121 \ m  + 2.71 \ m , -2.121 \ m + 3.59 \ m )

\vec{R} = ( 4.831 \ m , 1.469 \ m )

This is R in Cartesian representation, now, to find the magnitude we can use the Pythagorean theorem

|\vec{R}| = \sqrt{R_x^2 + R_y^2}

|\vec{R}| = \sqrt{(4.831 m)^2 + (1.469 m)^2}

|\vec{R}| = \sqrt{23.338 m^2 + 2.158 m^2}

|\vec{R}| = \sqrt{25.496 m^2}

|\vec{R}| = 5.049 m

To find the direction, we can use

\theta = arctan(\frac{R_y}{R_x})

\theta = arctan(\frac{1.469 \ m}{4.831 \ m})

\theta = arctan(0.304)

\theta = 16\°54'33''

As we are in the first quadrant, this is relative to the x axis.

3 0
3 years ago
Neutral hydrogen can be modeled as a positive point charge +1.6×10^−19C surrounded by a distribution of negative charge with vol
Archy [21]

Answer:

a) 1.082 × 10⁻¹⁹C  ( e = 1.6 × 10⁻¹⁹C)  

b) 3.466 × 10¹¹ N/C

Explanation:

a)

p(r) = -A exp ( - 2r/a₀)

Q = ₀∫^∞ ₀∫^π ₀∫^2xπ p(r)dV  =  -A  ₀∫^∞ ₀∫^π ₀∫^2π   exp ( - 2r/a₀)r² sinθdrdθd∅

Q = -4πA ₀∫^∞ exp ( - 2r/a₀)r²dr = -e

now using integration by parts;

A = e / πa₀³

p(r) =  - (e / πa₀³) exp (-2r/a₀)

Now Net charge inside a sphere of radius a₀ i.e Qnet is;

= e - (e / πa₀³)  ₀∫^a₀ ₀∫^π ₀∫^2π  r² exp (-2r/a₀)dr

= e - e + 5e exp (-2) = 1.082 × 10⁻¹⁹C  ( e = 1.6 × 10⁻¹⁹C)  

b)

Using Gauss's law,

E × 4πa₀ ² = Qnet / ∈₀

E = 4πa₀ ² × Qnet × 1/a₀²

E = 3.466 × 10¹¹ N/C

4 0
3 years ago
How many atoms of oxygen are there in one molecule of trinitrotoluene, if the chemical formula is C6H3(NO2)3?
kvasek [131]

。☆✼★ ━━━━━━━━━━━━━━  ☾  

2 x 3 = 6

Thus there are 6 atoms of oxygen in this molecule.

Have A Nice Day ❤    

Stay Brainly! ヅ    

- Ally ✧    

。☆✼★ ━━━━━━━━━━━━━━  ☾

6 0
3 years ago
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