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3 years ago

Which is colder, 0°C or 20°F?

Physics

2 answers:

Allushta [10]3 years ago

8 0

20 degrees F because 0 degrees celcius is around 32 degrees F

Mashutka [201]3 years ago

7 0

In order to compare the two temperatures, we need to convert 20°F into Celsius. The formula we need to use is:

$T(^{\circ}C)=\frac{5}{9}(T(^{\circ}F)-32)$

Substituting 20°F, we find

$T(^{\circ}C)=\frac{5}{9}(20^{\circ}F-32) =-6.7^{\circ}C$

And this is less than 0°C, so the answer is

20°F is colder than 0°C.

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Read 2 more answers

Oscilloscopes have parallel metal plates inside them to deflect the electron beam. These plates are called the deflecting plates

Alina [70]

Answer:

The capacitance of the deflecting plates is $C=1.59 pF$ .

Explanation:

The expression for the capacitance of the capacitor in terms of area and distance is as follows;

$C=\frac{\varepsilon _{0}A}{d}$

Here, C is the capacitance, A is the area, d is the distance and $\varepsilon _{0}$ is the absolute permittivity.

Convert the side of the square from cm to m.

s= 3.0 cm

s= 0.030 m

Calculate the area of the square.

$A= s_^{2}$

Put s= 0.030 m.

$A=(0.030)_^{2}$

$A=9\times10^{-4}m^{-2}$

Convert distance from mm to m.

d= 5.0 mm

$d=5\times10^{-3}m$

Calculate the capacitance of the deflecting plates.

$C=\frac{\varepsilon _{0}A}{d}$

Put $d=5\times10^{-3}m$ , $A=9\times10^{-4}m^{-2}$ and $\varepsilon _{0}=8.85\times 10^{-12}Fm^{-1}$ .

$C=\frac{(8.85\times 10^{-12})(9\times10^{-4})}{5\times10^{-3}}$

$C=1.59\times 10^{-12}F$

$C=1.59 pF$

Therefore, the capacitance of the deflecting plates is $C=1.59 pF$ .

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3 years ago