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RideAnS [48]
3 years ago
14

Which is colder, 0°C or 20°F?

Physics
2 answers:
Allushta [10]3 years ago
8 0
20 degrees F because 0 degrees celcius is around 32 degrees F 
Mashutka [201]3 years ago
7 0

In order to compare the two temperatures, we need to convert 20°F into Celsius. The formula we need to use is:

T(^{\circ}C)=\frac{5}{9}(T(^{\circ}F)-32)

Substituting 20°F, we find

T(^{\circ}C)=\frac{5}{9}(20^{\circ}F-32) =-6.7^{\circ}C


And this is less than 0°C, so the answer is

20°F is colder than 0°C.


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An object that is magnetic all of the time is called a.
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Bar magnets are permanent magnets. This means that their magnetism is there all the time and cannot be turned on or off as it can with electromagnets .

Explanation:

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2 years ago
Particle 1 and particle 2 have masses of m1 = 2.2 × 10-8 kg and m2 = 4.8 × 10-8 kg, but they carry the same charge q. The two pa
Lorico [155]

Answer:r_2=11.81 cm

Explanation:

Given

m_1=2.2\times 10^{-8} kg

m_2=4.8\times 10^{-8} kg

same charge on both masses

potential Energy due to Magnetic Field =Kinetic Energy of Particle

qV=\frac{mv^2}{2}

v=\sqrt{\frac{2qV}{m}}

and we know

Force due to magnetic field will Provide centripetal Force

qvB=\frac{mv^2}{r}

B=\frac{\sqrt{\frac{2Vm}{q}}}{r}

and B is equal for both particles

thus \frac{m}{r^2}=constant

\frac{m_1}{r_1^2}=\frac{m_2}{r_2^2}

r_2^2=\frac{4.8}{2.2}\times 8^2

r_2=11.81 cm

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Assume the following vehicles are all moving at the Sam speed .it would be harder to change the velocity of which vehicle . What
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A 6.0 m wire with a mass of 50 g, is under tension. A transverse wave, for which the frequency is 810 Hz, the wavelength is 0.40
MrRissso [65]

Answer:

a) t = 0.0185 s = 18.5 ms

b) T = 874.8 N

Explanation:

a)

First we find the seed of wave:

v = fλ

where,

v = speed of wave

f = frequency = 810 Hz

λ = wavelength = 0.4 m

Therefore,

v = (810 Hz)(0.4 m)

v = 324 m/s

Now,

v = L/t

where,

L = length of wire = 6 m

t = time taken by wave to travel length of wire

Therefore,

324 m/s = 6 m/t

t = (6 m)/(324 m/s)

<u>t = 0.0185 s = 18.5 ms</u>

<u></u>

b)

From the formula of fundamental frquency, we know that:

Fundamental Frequency = v/2L = (1/2L)(√T/μ)

v = √(T/μ)

where,

T = tension in string

μ = linear mass density of wire = m/L = 0.05 kg/6 m = 8.33 x 10⁻³ k gm⁻¹

Therefore,

324 m/s = √(T/8.33 x 10⁻³ k gm⁻¹)

(324 m/s)² = T/8.33 x 10⁻³ k gm⁻¹

<u>T = 874.8 N</u>

8 0
3 years ago
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