A 0.046 kg golf ball hit by a driver can accelerate from rest to 67 m/s in 1 ms while the driver is in contact with the ball. Ho
1 answer:
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Explanation:
It is given that,
The volume of a right circular cylindrical,
We know that the volume of the cylinder is given by :
............(1)
The upper area is given by :
For maximum area, differentiate above equation wrt r such that, we get :
r = 1.83 m
Dividing equation (1) with r such that,
Hence, this is the required solution.
Answer:
d= 7.32 mm
Explanation:
Given that
E= 110 GPa
σ = 240 MPa
P= 6640 N
L= 370 mm
ΔL = 0.53
Area A= πr²
We know that elongation due to load given as
A= 42.14 mm²
πr² = 42.14 mm²
r=3.66 mm
diameter ,d= 2r
d= 7.32 mm