Answer:
Explanation:
Let the cross sectional area be a cm .
volume of hydrometer inside liquid = 12 x a = 12 a
weight of liquid displaced = 12a x .8 x g = 9.6 a g
For free floatation of liquid
weight of hydrometer = weight of displaced liquid
9.6 a g = 100 g
a = 10.41 cm²
cross sectional area = 10.41 cm².
Answer:
12°F
Explanation:
Calculation for how much subcooling is there in the condenser
Since the CONDENSING TEMPERATURE for 417.4 psig discharge pressure is 120 degrees (120°) which means that the amount of subcooling that is there in the condenser will be calculated using this formula
Amount of Condenser subcooling= Condensing Temperature discharge pressure -Condenser outlet temperature
Let plug in the formula
Amount of Condenser subcooling=120°-108f
Amount of Condenser subcooling=12°F
Therefore the amount of subcooling that is there in the condenser will be 12°F
Answer:
Not balanced
Explanation:
The force pulling the object up is applying less force than the object pulling down, this means the object will move down
Answer:
Centrifugal Force = 45.65N
Explanation:
Given the following data;
Mass, m = 80kg
Radius = 487m
Velocity = 60km/h to m/s = 60*1000/3600 = 16.67m/s
To find the centrifugal force;
Centrifugal Force = mv²/r
Substituting into the equation, we have;
Centrifugal Force = 80*16.67²/487
Centrifugal Force = 80*277.89/487
Centrifugal Force = 2223.12/487
Centrifugal Force = 45.65N
Answer:
3.55 T
Explanation:
Applying,
F = BILsin∅.............. Equation 1
Where F = Force, B = magnetic Field, I = current, L = Length of the wire, ∅ = Angle between the wire and the magnetic field
make B the subject of the equation
B = F/ILsin∅.................. Equation 2
From the question,
Given: F = 2.45 N, L = 3.00 cm = 0.03 m, I = 23.0 A, ∅ = 90° (Perpendicular)
Substitute these values into equation 2
B = 2.45/(0.03×23×sin90)
B = 2.45/0.69
B = 3.55 T