X -> Y + 2Z
So there are 2 different particles. 1 mol of X produces
1 mol of Y and 2 moles of Z.
Kps = [Y] [Z]^2
We will call “s” (solubility) the molarity of X
So the molarity of Y+ is also “s” (same number)
And the molarity of Z is “2s” (twice as much)
Kps = s*(2s)^2 = s*4s^2=4s^3
If s is multiplied by 2:
Kps = 4*(2s)^3=4*2^3*s^3=4*8*s^3
So Kps is multiplied by 8.
C.
<span>Each atom has 19 proton
</span> the atomic number is the same as protons
You will need to turn this into scientific notation, so:
1.176 × 10^1 cm^2
To two significant figures means to two digits so since 7 is greater than 5, you will need to round up.
Final answer is:
1.2×10^1 cm^2
Answer:
a) M = 2 10³⁰ kg
, b)
= 5.81 10⁷ s
Explanation:
a) For this exercise let's use Newton's second law where force is the law of universal gravitation and acceleration is centripetal
G m M / R² = m a
a = v² / R
G M / R = V²
The orbit of the two planets is approximately circular, therefore the velocity module (speed) is constant
v = d / t
The distance is the length of the circular orbit
d = 2π R
G M / R = 4π² R² / T²
G M T² = 4π² R³
Let's write this equation for each planet
For the earth
The period is T = 3.16 10⁷ s and the radius of the orbit R = 1.5 10¹¹ m, let's calculate the mass of the sun
M = 4π² R³ / G T²
M = 4π² (1.5 10¹¹)³ / (6.67 10⁻¹¹ (3.16 10⁷)²)
M = 133.24 10³³ / 66.60 10³
M = 2 10³⁰ kg
b) For this part we write this equation for the two points
For the earth
² = (4π² / G M)
³
For mars
² = (4π² / G M)
³
Let's divide the two expressions
² /
² =
³ /
³
They indicate that the orbit of Mars is
= 1.5 
² /
² = (1.5
/
)³
² =
² 1.5³
² = (3.16 10⁷)² 1.5³
= √ (33.70 10¹⁴)
= 5.81 10⁷ s