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Svetllana [295]
3 years ago
5

A spaceship orbiting earth flies to the moon. How is the gravitational force pulling on the spaceship related to the distance th

at the spaceship is from the earth?
A. As the distance from the earth increases, the gravitational pull on the spaceship would decrease.


B. The gravitational pull of the earth is constant and therefore the gravitational pull on would not change.


C. As the distance from the earth decreases, the gravitational pull on the spaceship would decrease.


D. There is no gravity on the moon and therefore only the earth will exert gravitational force on the spaceship.
Physics
2 answers:
ioda3 years ago
7 0
A is Correct, because as you increase the distance  between the spaceship and Earth the gravitational force would be less and according to Isaac Newton's Gravitational formula F = (G Mm)/r^2, the distance r is in inverse relationship to the Force.  
Butoxors [25]3 years ago
4 0
The correct answer is A
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A cat walks along a plank with mass M= 7.00 kg. The plank is supported by two sawhorses. The center of mass of the plank is a di
solong [7]

Answer:

Before the plank will tip cat will walk 1.652 m

Explanation:

Mass of the cat along with plank m_1=7kg

Center of mass of the plank d_1=0.850m

Mass of cat m_2=3.6kg

We have to find how far right of sawhorse B.

Plank will tip when weight of the cat about B is greater than the torque by the weight of the plank.

Balancing the the torque

m_1gd_1=m_1gd_2

7\times 9.8\times 0.850=3.6\times 9.8\times d_2

d_2=1.652m

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3 years ago
A tennis ball moving at a speed of 4 m/s, collides with a bowling ball at rest. The tennis ball bounces back in the direction op
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Answer:

Both experienced the same magnitude impulse

Explanation:

This is because, the impulse force is internal to the system of both the tennis ball and the bowling ball. It is an action-reaction pair. So, the force exerted on the tennis ball by the bowling ball equals in magnitude to the force exerted by the tennis ball on the bowling ball although, they are in opposite directions. This, both experienced the same magnitude impulse.

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7 0
3 years ago
a person using a machine applies a force of 100 newton's over a distance of 10 Meters to raise a 500 n object 1.5 meters what is
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Answer:

Work done by the machine (W) =  500 × 1.5 = 750 J

Work supplied to the machine (W) = 100 × 10 = 1000 J

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The escape velocity is defined to be the minimum speed with which an object of mass m must move to escape from the gravitational
s344n2d4d5 [400]

Answer:

v = √2G M_{earth} / R

Explanation:

For this problem we use energy conservation, the energy initiated is potential and kinetic and the final energy is only potential (infinite r)

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If we do Rinf = infinity     1 / Rinf = 0

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The mechanical energy is conserved  

 

      Em = -G m1  M_{earth} / R

      Em = - G m1  M_{earth} / R

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2 years ago
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