Question

A mover slides a refrigerator weighing 650 N at a constant velocity across the floor a distance of 8.1 m. The force of friction between the refrigerator and the floor is 230 N. How much work has been performed by the mover on the refrigerator?

Answer 1

Answer:

1863 J

Explanation:

F = Force moving the object

f = Frictional force = 230 N

The forces in the horizontal direction have the force balance

$F-f=0\\\Rightarrow F=f\\\Rightarrow F=230\ \text{N}$

So, the force by which the object is being pushed is $230\ \text{N}$

s = The displacement of the object = 8.1 m

Work done is given by

$W=Fs\\\Rightarrow W=230\times 8.1\\\Rightarrow W=1863\ \text{J}$

The work done by the mover is 1863 J.