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Nitella [24]
3 years ago
6

Mary is investigating the densities of objects. She is going to use the table below to record her results. Which of these can sh

e find using a ruler?

Physics
1 answer:
Dennis_Churaev [7]3 years ago
8 0

<u><em /></u>

<u><em>answer</em></u>

block of aluminium

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An elevator manufacturing company is stress-testing a new elevator in an airless test shaft. The elevator is traveling at an unk
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Answer:

3.192 m/s

Explanation:

t = Time taken = 0.900 seconds

u = Initial velocity

v = Final velocity

s = Displacement = 1.1 meters

a = Acceleration due to gravity = 9.81 m/s²

s=ut+\frac{1}{2}at^2\\\Rightarrow u=\frac{s-\frac{1}{2}at^2}{t}\\\Rightarrow u=\frac{1.1-\frac{1}{2}\times 9.81\times 0.9^2}{0.9}\\\Rightarrow u=-3.192\ m/s

Velocity of the elevator when it snapped is 3.192 m/s

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Missy watched a storm last night with her brother. During the storm, she witnessed a large lightening bolt. What energy transfor
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The answer to the question is light

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An electroscope is a device that has small gold foil strips suspended from a metal rod. A student brings a negatively charged ro
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I think it is neutral
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The aurora is caused when electrons and protons, moving in the earth’s magnetic field of ≈5.0×10−5t, collide with molecules of t
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The question is incomplete. I can help you by adding the information missing. They want you to calculate a) the radius of the cyclotron orbit for an electron with speed 1.0 * 10^6 m/s^2 and b) the radius of a cyclotron orbit for a proton with speed 5.0 * 10^4 m/s.

The two tasks involve combining the equations of the magnectic force and the centripetal force in a circular motion.

When you do that, you will obtain an expression to find the radius of the circular motion, which is the radius of the cyclotron that impulses the particles.

a)

Magentic force, F = q*v*B

q is the charge of the electron = 1.6 * 10^ -19 C
v is the speed = 1.0 * 10 ^ 6 m/s
B is the magentic field = 5.0 * 10 ^-5 T

Centripetal force, F = m*Ac = m * v^2 / R

where,

Ac = centripetal acceleration
m = mass of the electron = 9.11 * 10 ^-31 kg
R = the radius of the orbit

Now equal the two forces: q*v*B = m * v^2 / R => R =  m*v / (q*B)

=> R = (9.11 * 10^31 kg) (1.0*10^6m/s) / [ (1.6 * 10^-19C)* (5.0 * 10^-5T) ]

=> R = 0.114 m

b) The equations are the same, just now use the speed, charge and mass of the proton instead of those of the electron.

R = m*v / (qB) = (1.66*10^-27 kg)(5.0*10^4 m/s) / [(1.6*10^-19C)(5*10^-5T)]

=> R = 10.4 m

 

4 0
4 years ago
I NEED HELP PLZ. can some one explain partial variation ​
dezoksy [38]

Answer:

Explanation:

Partial Variation is a relation that is of the form y = mx+b. The graph of y = mx+b is a straight line with the slope of m and a y-intercept of b. ... The relation y = mx +b represents partial variation because the value of y varies partially with the value of x.

8 0
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