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Fofino [41]
4 years ago
8

A particle with charge 5 . 0- µ C is placed at the corner of a cube. (Physics Help)? A particle with charge 5.0-µC is placed at

the corner of a cube. The total electric flux in N * m^2 C through all sides of the cube is: B) 7.1 x 10^4 D) 1.4 x 10^5
Physics
1 answer:
Svetradugi [14.3K]4 years ago
6 0

Gauss law states that the electric flux through any closed surface is proportional to the net electric charge inside the surface. This is expressed mathematically in the form of:

Φ = Q / εo

Where,

Φ = the electric flux = unknown (which we have to find for)

Q = the net electric charge = 5.0 µC = 5 E-6 C

εo = the permittivity of free space = a constant value = 8.85 E-12 C^2 / N m^2

Plugging in the values into the equation will result in:

Φ = 5 E-6 C / (8.85 E-12 C^2 / N m^2)

Φ = 564,971.75 Wb = <span>5.6 x 10^5 Wb </span>

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Determine the inductance L of a 0.65-m-long air-filled solenoid 3.2 cm in diameter containing 8400 loops.
den301095 [7]

Answer:

The inductance is  L  = 0.1097 \ H

Explanation:

From the question we are told that

  The  length is  l  =  0.65 \ m

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    The  number of loops is  N  =  8400

Generally the radius is evaluated as

       r = \frac{ 0.032 }{2}  =  0.016 \ m

The  inductance is mathematically represented as

      L  =  \frac{ \mu_o  *  N^2  * A }{ l }

Here \mu_o is the permeability of free space with value  \mu_o   = 4\pi * 10^{-7} N/A^2

A is the cross-sectional area which is mathematically evaluated as

             A =  \pi  r^2

=>        A =  3.142 *  (0.016)^2

=>        A =  0.000804 \ m^2

 =>  L  =  \frac{   4\pi * 10^{-7} *  8400^2  * 0.000804  }{ 0.65 }

=>    L  = 0.1097 \ H

5 0
3 years ago
The force of gravity is<br> _m/s2
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Answer:

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