two balls are dropped to the ground from the different heights. one is dropped 1.5s after the other, but they reach the ground a
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To solve this problem it is necessary to apply the kinematic equations of motion.
By definition we know that the position of a body is given by
Where
Initial position
Initial velocity
a = Acceleration
t= time
And the velocity can be expressed as,
Where,
For our case we have that there is neither initial position nor initial velocity, then
With our values we have , rearranging to find a,
Therefore the final velocity would be
Therefore the final velocity is 81.14m/s