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Answer:- Formula of the hydrate is and it's name is Iron(III)sulfate pentahydrate.
Solution:- As per the given information, there is 18.4% water in the hydrate. If we assume the mass of the hydrate as 100 grams then there would be 18.4 grams of water and 81.6 grams of Iron(III)sulfate present in the hydrate.
Molar mass for Iron(III)sulfate is 399.88 gram per mol and the molar mass for water is 18.02 gram per mol.
We will calculate the moles of Iron(III)sulfate and water present in the compound on dividing their grams by their molar masses as:
=
=
Now, the next step is to calculate the mol ratio and for this we divide the moles of each by the least one of them means whose moles are less. Here, the moles of Iron(III)sulfate are less than moles of water. So, we divide the moles of each by 0.204.
= 1
= 5
There is 1:5 mol ratio between Iron(III)sulfate and water. So, the formula of the hydrate is and the name of the hydrate is Iron(III)sulfate pentahydrate.
Answer:
The value is
Explanation:
From the question we are told that
The initial volume of the fluorocarbon gas is
The final volume of the fluorocarbon gas is
The initial temperature of the fluorocarbon gas is
The final temperature of the fluorocarbon gas is
The initial pressure is
The final pressure is
Generally the equation for adiabatically reversible expansion is mathematically represented as
Here R is the ideal gas constant with the value
So
=>
Generally adiabatic reversible expansion can also be mathematically expressed as
=>
=>
=>
So
=>