The absolute value of the difference in electronegativity (ΔEN) of two bonded atoms provides a rough measure of the polarity to be expected in the bond and, thus, the bond type. When the difference is very small or zero, the bond is covalent and nonpolar. When it is large, the bond is polar covalent or ionic.
Answer:
Vapour pressure of benzene over the solution is 253 torr
Explanation:
According to Raoult's law for a mixture of two liquid component A and B-
vapour pressure of a component (A) in solution = ![x_{A}\times P_{A}^{0}](https://tex.z-dn.net/?f=x_%7BA%7D%5Ctimes%20P_%7BA%7D%5E%7B0%7D)
vapour pressure of a component (B) in solution = ![x_{B}\times P_{B}^{0}](https://tex.z-dn.net/?f=x_%7BB%7D%5Ctimes%20P_%7BB%7D%5E%7B0%7D)
Where
are mole fraction of component A and B in solution respectively
are vapour pressure of pure A and pure B respectively
Here mole fraction of benzene in solution is 0.340 and vapour pressure of pure benzene is 745 torr
So, vapour pressure of benzene in solution = ![0.340\times 745 torr](https://tex.z-dn.net/?f=0.340%5Ctimes%20745%20torr)
= 253 torr
The element that will have the lowest electronegativity is an element with a small number of valence electrons and a large atomic radius.
Electronegativity of an element is the ability or power of that element in a molecule to attract electrons to its Valence electrons. The following are the properties of electronegativity:
- It increases across a period from left to right of the periodic table,
- It decreases down the periodic table groups
- Group 1 elements are the least (lowest) electronegative elements. These elements have the lowest valence electrons with a large atomic radius.
- Group 7 elements are the most electronegative elements.
Atomic radius of elements increase down a group because of a progressive increase in the number of shells occupied by electrons which increases the size. But it decreases across a period because electrons are accommodated within the same shell leading to greater attraction by the protons in the nucleus.
Learn more about electronegativity of elements here:
brainly.com/question/20348681
Answer:
![d=1.6\ g/cm^3](https://tex.z-dn.net/?f=d%3D1.6%5C%20g%2Fcm%5E3)
Explanation:
Given that,
The dimension of a square chunk of plastic is 5 cm × 5 cm × 5 cm
Mass, m = 200 g
We need to find its density
Density = mass/volume
It will form a cube. It volume = side³
So,
![d=\dfrac{200\ g}{5^3\ cm^3}\\\\d=1.6\ g/cm^3](https://tex.z-dn.net/?f=d%3D%5Cdfrac%7B200%5C%20g%7D%7B5%5E3%5C%20cm%5E3%7D%5C%5C%5C%5Cd%3D1.6%5C%20g%2Fcm%5E3)
Hence density is ![1.6\ g/cm^3](https://tex.z-dn.net/?f=1.6%5C%20g%2Fcm%5E3)