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butalik [34]
3 years ago
9

Un cable guía de 600 pies esta sujeto a la parte superior de una torre de comunicaciones. Si el cable forma un ángulo de 65° con

la Tierra. ¿Cuál es la altura de la torre de comunicaciones?
Mathematics
1 answer:
natita [175]3 years ago
8 0

Answer:

La torre tiene 543.78 pies de altura.

Step-by-step explanation:

Podemos pensar en esta situación como si fuera un triángulo rectángulo, donde el cable es la hipotenusa y la torre es uno de los catetos. (Abajo se puede ver un dibujo de esta situación).

Nosotros queremos encontrar el valor de H, que es el cateto opuesto al ángulo conocido de 65°.

Entonces simplemente podemos usar la relación:

Sin(θ) = (cateto opuesto)/(hipotenusa)

donde:

cateto opuesto = H

θ = 65°

hipotenusa = 600 ft

sin(65°)  = H/600ft

sin(65°)*600ft = H = 543.78 ft

La torre tiene 543.78 pies de altura.

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The given polynomial is not a prime polynomial.

Given the polynomials, we have to choose the polynomial which is prime.

A polynomial with integer coefficients that cannot be factored into lower degree polynomials is Prime polynomials.

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\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}

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\quad x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

\mathrm{For\:}\quad a=7,\:b=-33,\:c=-10

x_{1,\:2}=\frac{-\left(-33\right)\pm \sqrt{\left(-33\right)^2-4\cdot \:7\left(-10\right)}}{2\cdot \:7}

x_{1,\:2}=\frac{-\left(-33\right)\pm \sqrt{\left(-33\right)^2-4\cdot \:7\left(-10\right)}}{2\cdot \:7}

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x_1=\frac{-\left(-33\right)+37}{2\cdot \:7},\:x_2=\frac{-\left(-33\right)-37}{2\cdot \:7}

x=5,\:x=-\frac{2}{7}

Therefore the factor is (x-5) and (7x+2).

can be factored

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To learn more about the prime polynomial visit:

brainly.com/question/26388060

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