Answer:
Option 2. √3 x V
Explanation:
Let the velocity of satellite orbiting Earth at r be V
Let the velocity of the satellite orbiting at 3r be V1
V (orbiting at r) = √(2gr)
V1 (orbiting at 3r) = √(2g3r)
Now let us find the ratio of V1(orbiting at 3r) to V(orbiting at r) .
This is illustrated below
V1 / V = √(2g3r)/√(2gr)
V1 / V = √3
Cross multiply to express in linear form
V1 = V x√3
V1 = √3 x V
From the above illustrations, we can see that the velocity of the satellite when it is moved to an orbital radius of 3r is: √3 x V
Answer:
Explanation:
Acceleration is equal to the change in velocity over the change in time, or
where the change in velocity is final velocity minus initial velocity. Filling in:
Note that I made the backward velocity negative so the forward velocity in our answer will be positive.
Simplifying that gives us:
and then isolating the final velocity, our unknown:
3.0(6.0) = v + 3.0 and
3.0(6.0) - 3.0 = v and
18 - 3.0 = v so
15 m/s = v and because this answer is positive, that means that the car is no longer rolling backwards (which was negative) but is now moving forward.
The earth rotates from west to east :)
Being the planet closest to the sun, Mercury must be the one
with the shortest year. That's how gravity works.
